Molar mass MgCO3 => 84.31 g/mol
1 mole MgCO3 ----------- 84.31 g
1.5 moles MgCO3-------- ??
1.5 x 84.31 / 1 => 126.465 g
Answer:
45200J
Explanation:
Given parameters:
Heat of vaporization of water = 2260J/g
Mass of steam = 20g
Temperature = 100°C
Unknown:
Energy released during the condensation = ?
Solution:
This change is a phase change and there is no change in temperature
To find the amount of heat released;
H = mL
m is the mass
L is the latent heat of vaporization
Insert the parameters and solve;
H = 20g x 2260J/g
H = 45200J
Answer: I believe it’s the second one
(F)
Explanation:
Answer:
C: metals donate electrons to non metals
Explanation:
