Find the mass of C in the 2.657 g CO2:
(2.657 g CO2) / (44.01 g/mol) = 0.06037 mol CO2
Since each mole of CO2 also has 1 mole of C, this is equivalent to 0.06037 mol C.
Find the mass of H in the 1.089 g H2O:
(1.089 g H2O) / (18.02 g/mol) = 0.06043 mol H2O
Since 1 mol H2O has 2 mol H, this is equivalent to (0.06043)*2 = 0.1209 mol H.
Taking the ratio of H to C: 0.1209 / 0.06037 = 2.002 ~ 2
Therefore, the empirical formula of isobutylene is CH2.
Percentage yield= actual yield/theoretical yield x100
So you would have to do-
15/22 x 100. Hope this helps!!
Sharing of valence electrons.
Explanation:
In a covalent bonds, there is sharing of the valence electrons used in bonding between the two combining species.
The atoms taking part do not have a wide electronegativity difference between them and so they share the valence electrons to complete their octet and ensure their stability.
- For the formation of this bond type, each of the atom requires a odd or unpaired electrons.
- Covalent bonds are formed between atoms having zero or very small electronegativity difference.
Learn more:
Covalent bonds brainly.com/question/10903097
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