To check if a piecewise defined function is continuous, you need to check how the pieces "glue" together when you step from one domain to the other.
So, the question is: what happens at x=3? If you reach x=3 from values slightly smaller than 3, you obey the rule f(x)=log(3x). So, as you approach 3, you get values closer and closer to
Similarly, if you reach x=3 from values slightly greater than 3, you obey the rule f(x)=(4-x)log(9). So, as you approach 3, you get values closer and closer to
So, the function is continuous at x=3, because both pieces approach log(9) as x approaches 3.
Answer:
5/2 kg
Step-by-step explanation:
The ratio here is 2:6. 2 plus 6 is 8.
Then (2/8) times 10 kg represents the amount of compost needed; that comes to 20/8 kg, or 10/4 kg, or 5/2 kg.
4y + 3 > 23 subtract 3 from both sides
4y > 20 divide both sides by 4
y > 5
-2y > -2 divide both sides by -2 (the order changes)
y < 1
(-oo, 1) ∪ (5, oo)
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Answer:
A quadralateral is any shape that has 4 sides ...
Step-by-step explanation:
rectangle
square
rhombus
Answer:
63/5 or 12 (3/5)
Step-by-step explanation:
It is 8 whole (1 ÷ 5) plus 4 whole (2 ÷ 5)
So,we can write it as 8 (1/5) + 4 (2/5)
Then we will take those mixed fractions to improper fractions by using the rule of multiplication.
8 will be multiplied by 5 and then the value will be added to 1. Same rule will be applied for the second fraction.
(41÷5) + (22÷5)
Now we will take L.C.M. (Least common multiple) for both denominators 5 and 5. The L.C.M of 5 and 5 = 5
(41 + 22)/5
= 63/5
It is the answer. Also we can make this improper fraction into mixed fraction by dividing the whole number by 5.
12 (3/5)
