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Murrr4er [49]
2 years ago
9

A 120 V potential difference is applied to a space heater that dissipates 674 W during operation. (a) What is its resistance dur

ing operation? (b) At what rate do electrons flow through any cross section of the heater element?
Physics
2 answers:
Annette [7]2 years ago
6 0

Answer:

(a) 21.36 ohms

(b) 5.62 A

Explanation:

Parameters given:

Potential difference, V = 120 V

Power, P = 674 W

(a) Power is given as:

P = V²/R

Where R is resistance

=> R = V²/P

R = 120²/674

R = 14400/674

R = 21.36 ohms

(b) Power is also given as:

P = I*V

Where I = Current (time rate of flow of Electric charge)

=> I = P/V

I = 674/120

I = 5.62 A

OverLord2011 [107]2 years ago
3 0

Answer:

Explanation:

Given:

V = 120 V

Power = 674 W

A.

Resistance, R;

P = I × V

= V^2/R

R = 120^2/674

= 21.36 ohms

B.

dQ/dt = I

Using ohms law,

Current, I = V/R

= 120/21.36

= 5.62 C/s(A)

1 electron = 1.602 × 10^-19 C

Number of electrons in 1 second = 5.62/1.602 × 10^-19

= 3.51 × 10^19 per second

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Which of the following scenarios would be optimal for obtaining a date from radioactive decay using these isotopes: 87Rb, 147Sm,
REY [17]

Answer:

a) 238U, 40K and 87Rb, b)   235U and to a lesser extent 40K , c)  he 235U,

d) possibility is 14C , e)this period would be ideal for 14C , f) 14C should be used since it is the one with the least average life time, even though the measurements must be very careful

Explanation:

One of the applications of radioactive decay is the dating of different systems.

To do this, the quantity of radioactive material in a meter is determined and with the average life time, the time of the sample is found.

Let's write the half-life times of the given materials

87Rb T ½ = 4.75 1010 years

147Sm T ½ = 1.06 1011 years

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238U = 4.47 109 years

40K = 1,248 109 years

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we already have the half-life of the different elements given

a) meteors. As these decomposed in the formation of the solar system, their life time is around 3 109 to 5 109 years, so it is necessary to look for elements that have a life time of this order, among the candidates we have 238U, 40K and 87Rb if these elements were at the moment of the formation of these meteors, there must still be rations in them, instead elements 14C already completely adequate

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Answer:

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