All categories

2 years ago

State 2 postulates of kinetic theory of gases of 45 of 450

Chemistry

1 answer:

Ber [7]2 years ago

8 0

Explanation:

The kinetic theory of gases is basically used to explain the behavior of gases.

Some of the assumptions of the theory is as follow:

A gas is composed of large number of identical molecules at different speeds.
The space occupied by the gas molecules themselves are negligible compared to the volume of the space they occupy.
The molecules are independent of each other and the force of attraction and repulsion between them are negligible.
The molecules collide elastically with one another and with the walls of the container.
The temperature of gas is a measure of their average kinetic energy.

learn more:

molecular theory brainly.com/question/12362857

#learnwithBrainly

You might be interested in

What is the definition of a catalyst?

aleksandrvk [35]

Answer:

I think the best answer is (5) because catalyst are known to speed up a reaction without being changed

7 0

3 years ago

2. Energy cost of plasma generation of NO, NO2, and NO3 in air (or air bubble) is about 20 eV per N-atom. 100 W plasma system ha

svet-max [94.6K]

Answer:

0.0933 moles/Litre

Explanation:

We assume that the number of moles of N- used is equal to the number of moles of Nitrogen containing compounds that are generated due to the fact that the nitrogen containing compound that are produced contain only one nitrogen in each atom. As such, finding the amount of nitrogen used up explains the amount of compound formed. This can be expressed as follows:

Energy cost = $\frac{20ev}{N- atom}$

Given that:

Energy = 100 W for 60 minutes

100 W = 100 J/s

= 100 J/s × (60 × 60) seconds

= 3.6 × 10⁵ J

Let now convert 3.6 × 10⁵ J to eV; we have:

= ( 3.6 × 10⁵ × 6.242 × 10¹⁸ )eV

= 2.247 × 10²⁴ eV

So, number of N-atom used up to form compounds will now be:

= 2.247 × 10²⁴ eV × $\frac{1}{20eV} N-atom$

= 1.123 × 10²³ N-atom

To moles; we have:

= $\frac {1.123*10^{23}} {6.023*10^{23}}$

= 0.186 moles

However, we are expected to leave our answer in concentration (i.e in moles/L)

since we are given 2L

So; 0.186 moles ⇒ $\frac{0.186 moles}{2 Litre}$

= 0.0933 moles/Litre

3 0

3 years ago

Write down the reaction of sodium hydioxide with hydrochloric acid in words and symbols.

ZanzabumX [31]

Hello!

the reaction:
sodium hydroxide + hydrochloric acid = sodium chloride

NaOH + HCl -> NaCl + H2O

if this helps, click “thanks” :)

- emily

5 0

3 years ago

A chemist dissolves of pure potassium hydroxide in enough water to make up of solution. Calculate the pH of the solution. (The t

Leya [2.2K]

Answer:

12.99

Explanation:

A chemist dissolves 716. mg of pure potassium hydroxide in enough water to make up 130. mL of solution. Calculate the pH of the solution. (The temperature of the solution is 25 °C.) Be sure your answer has the correct number of significant digits.

Step 1: Given data

Mass of KOH: 716. mg (0.716 g)

Volume of the solution: 130. mL (0.130 L)

Step 2: Calculate the moles corresponding to 0.716 g of KOH

The molar mass of KOH is 56.11 g/mol.

0.716 g × 1 mol/56.11 g = 0.0128 mol

Step 3: Calculate the molar concentration of KOH

[KOH] = 0.0128 mol/0.130 L = 0.0985 M

Step 4: Write the ionization reaction of KOH

KOH(aq) ⇒ K⁺(aq) + OH⁻(aq)

The molar ratio of KOH to OH⁻is 1:1. Then, [OH⁻] = 0.0985 M

Step 5: Calculate the pOH

We will use the following expression.

pOH = -log [OH⁻] = -log 0.0985 = 1.01

Step 6: Calculate the pH

We will use the following expression.

pH + pOH = 14

pH = 14 - pOH = 14 -1.01 = 12.99

8 0

2 years ago

(a) if a sample containing 2.00 ml of nitroglycerin is detonated, how many total moles of gas are produced? (b) if each mole of

gregori [183]

Detonation of nitroglycerin:

$4C_3H_5N_3O_9 ------\ \textgreater \ 12CO_2+6N_2+O_2+H_2O$

Mass nitroglycerin = 2.00 mL x 1.592 g/mL = 3.184 g

Moles = mass / molar mass = 3.184 g/ 227.0872 g/mol = 0.01402

the ratio between nitroglycerin and Carbon dioxide is 4 : 12
So, moles CO2 = 0.01402 x 12 / 4 =0.0420

the ratio between nitroglycerin and N2 is 4 : 6
moles N2 = 0.01402 x 6 / 4 =0.0841

the ratio between nitroglycerin and O2 is 4 : 1 
moles O2 = 0.01402 x 1 / 4 = 0.0035

the ratio between nitroglycerin and water is 4 : 1 
in the same way moles water = 0.005258 

total moles = 0.0420 + 0.0841 + 0.0035 + 0.005258 = 0.130758

0.130758 x 55 = 5.78 L 

Mass N2 = 0.0841 mol x 28.0134 g/mol = 2.3548 g

6 0

2 years ago