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Taya2010 [7]
2 years ago
9

Determine the equilibrium constant, K, for the equilibrium below given the

Chemistry
1 answer:
meriva2 years ago
5 0

Answer:

or reactions that are not at equilibrium, we can write a similar expression called the reaction quotient QQQ, which is equal to K_\text cK

c

​

K, start subscript, start text, c, end text, end subscript at equilibrium.

Explanation:

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Using the spectra data below, which structure best matches this data? c4h8o 1h nmr triplet at 1.05 ppm (3h) singlet at 2.13 ppm
Delicious77 [7]

Answer:

Butan-2-one

Explanation:

1. 1700 cm⁻¹

A strong peak near 1700 cm⁻¹ is almost certainly a carbonyl (C=O) group.

2. Triplet-quartet

A triplet-quartet pattern indicates an ethyl group.

The 2H quartet is a CH₂ adjacent to a CH₃. The peak normally occurs at δ 1.3, but it is shifted 1.2 ppm downfield to δ 2.47 by an adjacent C=O group.

The 3H triplet at δ 1.05 is the methyl group. It, too, is shifted downfield from its normal position at δ 0.9. The effect is smaller, because the methyl group is further from the carbonyl.

3. 3H(s) at δ 2.13

This indicates a CH₃ group with no adjacent hydrogen atoms.

It is shifted 0.8 ppm downfield to δ 2.13 by the adjacent C=O group.

4. Identification

The identified pieces are CH₃CH₂-, -(CO)-, and -CH₃. There is only one way to put them together: CH₃CH₂-(C=O)-CH₃.

The compound is butan-2-one.

5 0
2 years ago
What might be a scientific question
AURORKA [14]

Answer:

Example of a scientific question:

Does the angle of a ramp change the distance a toy car will travel?

Explanation:

3 0
2 years ago
Need help <br>1/6 + 1/8 =
pogonyaev

1/6 + 1/8 = 7/24

24

≅ 0.2916667

6 0
3 years ago
What causes polar bonds
yulyashka [42]

Answer:

Bonds are polar when one element in a compound is more electronegative than the other. This creates a dipole in the molecule where one end of the molecule is partially positive and one end is partially negative

Explanation:

8 0
3 years ago
Need help with this can some please help
vekshin1
I believe you would just put a 2 in front of NH3 and keep the other ones as 1
7 0
3 years ago
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