The value of delta H° for aniline = 6415 Kj/mol
<u><em>calculation</em></u>
Step 1: find heat
Q (heat) = C (specific heat capacity) x ΔT (change in temperature)
C= 4.25 kj/c°
ΔT = 69.8-29.5 = 40.3 c°
Q= 4.25 kj/c x 40.3 c = 171.28 kj
Step 2: find the moles of aniline
moles = mass/molar mass
= 2.49 g/ 93.13 g/mol =0.0267 moles
Step 3: find delta H
171.28 kj/0.0267 mol = 6415 kj/mol
since the reaction is exothermic delta H = 6415 Kj/mol
The answer is rings, I know this because i took a test about it and I got it right
The answer is (1) 1.3 M. The first thing you need to do is to convert the unit of gram to mole. The mol number of LiF is 52/26=2 mol. Then using the volume to calculate the molarity: molarity=2/1.5=1.3 M.
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