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3 years ago

PLZ HELP ASAP THIS IS DUE IN AN HOUR

Chemistry

1 answer:

Llana [10]3 years ago

7 0

B I think that’s what my mom said

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What 2 materials mixed together forms a solution?

Charra [1.4K]

Lemonade mix and water

Solvent: Water
Solute: Lemonade mix

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3 years ago

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Table salt is sodium chloride and has the chemical formula of NaCl. What is the ratio of sodium atoms to chlorine atoms? (8.5D)

astra-53 [7]

Answer:

Explanation:Table salt is sodium chloride and has the chemical formula of NaCl. What is the ratio of sodium atoms to chlorine atoms? (8.5D)

Answer

А 2:1

1:1

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2 years ago

What would make bromide salt insoluble in water?

anzhelika [568]

Its doesn't dissolve in water!

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2 years ago

Does this sound catchy or invite you to read more? "GMOs and pesticides are general amongst farmers for generations and should n

siniylev [52]

Answer:

It sounds fine, but it may be a bit too long. It's difficult to shorten things like this, but getting more straight to the point would give it that "catchy" feel.

Explanation:

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2 years ago

Will GIVE BRAINLIEST --A student makes a standard solution of potassium hydroxide by adding 14.555 g to 500.0 mL of water. Answe

leva [86]

Answer:

0.5188 M or 0.5188 mol/L

Explanation:

Concentration is calculated as molarity, which is the number of moles per litre.

***Molarity is represented by either "M" or "c" depending on your teacher. I will use "c".

The formula for molarity is:

$c = \frac{n}{V}$

n = moles (unit mol)

V = volume (unit L)

Find the molar mass (M) of potassium hydroxide.

$M_{KOH} = \frac{39.098 g}{mol}+\frac{16.000 g}{mol}+\frac{1.008 g}{mol}$

$M_{KOH} = 56.106 \frac{g}{mol}$

Calculate the moles of potassium hydroxide.

$n_{KOH} = \frac{14.555 g}{1}*\frac{1mol}{56.106g}$

$n_{KOH} = 0.25941(9)mol$

Carry one insignificant figure (shown in brackets).

Convert the volume of water to litres.

$V = \frac{500.0mL}{1}*\frac{1L}{1000mL}$

$V = 0.5000L$

Here, carrying an insignificant figure doesn't change the value.

Calculate the concentration.

$c = \frac{n}{V}$

$c = \frac{0.25941(9)mol}{0.5000 L}$

$c = 0.5188(3) \frac{mol}{L}$ <= Keep an insignificant figure for rounding

$c = 0.5188 \frac{mol}{L}$ <= Rounded up

$c = 0.5188M$ <= You use the unit "M" instead of "mol/L"

The concentration of this standard solution is 0.5188 M.

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3 years ago