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Andrews [41]
2 years ago
7

6.Which of the following is NOT true about the lens?

Chemistry
1 answer:
ipn [44]2 years ago
7 0
The answer is A btw
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Write an introductory text about metals, adding details you know
Serggg [28]

Answer:

See below

Explanation:

Most of the elements found on earth are metals. A look at the periodic table shows that these elements occupy the entire left-hand stretch of the table, from the main group, through the transition metals, lanthanides, actinides, alkali and alkaline earth elements. One element included here, hydrogen, is rarely classified as a metal. On earth, hydrogen is a gas, and it is usually classified as a non-metal, like oxygen and nitrogen. However, at very low temperatures and very high pressures, hydrogen is a solid, and under the right conditions it is expected to behave more like a metal. It is thought that gas giants, such as Jupiter and Saturn in our solar system, may have metallic hydrogen cores. Metallic elements are not generally found as single atoms. Instead, the atoms in an element such as iron cluster together to make a larger structure. The materials formed in this way have some similar properties. Metals are shiny. Metals are malleable; they can be bent and formed into different shapes (at least when heated). Metals are good conductors of electricity. In metals, large groups of atoms cluster together. Metal atoms form large, extended arrays, with the atoms repeating in specific patterns throughout the solid.

The properties of metals are really important. The fact that metals are malleable allows them to be formed into sheets that can be used to make cars, airplanes, railway lines, cargo containers and ships, as well as more delicate items such as jewelry and surgical tools. A related property, ductility, allows metals to be stretched into long, thin wires. Together with the conductivity of metals, this property allows transmission lines to carry electricity from generating stations to people like you. Sometimes, the source of electricity is hundreds of miles away; electricity used to power a laptop in New York may come from places like La Grande Baleine or James Bay, in northwestern Quebec. Some of these properties can be understood by thinking about the structure of metallic elements. A great deal of our structural understanding of metals and other materials comes from x-ray diffraction studies. A very focused beam of x-rays can be sent into a material, where they will bounce off the atoms and scatter in different directions. The outcome sounds chaotic, but if the solid is highly organized, the x-rays behave in very predictable ways. The result is an x-ray diffraction pattern. A diffraction pattern is a little like the pattern of ripples on a pond when a stone is thrown into calm water. The pattern can be studied and decoded mathematically to find the locations of the atoms within the material. X-ray diffraction can reveal the atomic-level structures of highly ordered materials such as metals. What does x-ray diffraction tell us? Evidently, a chunk of metal is not just a mass of atoms stuck together randomly. Instead, the atoms arrange themselves in neat layers in very specific ways. These layers of atoms sit on top of each other to form a three-dimensional solid. One of the properties that results from this organized arrangement of atoms is the malleability of metals. If you take a nice, soft metal such as copper, after annealing it in a fire or oven, it can be bent and shaped easily. With copper, this can be done even after the metal has cooled to room temperature. When you bend the copper, you are actually causing layers of atoms to slide over each other, until you stop bending and they come to rest in a new location. If you have ever done this, you'll know that the more you work with the copper, the harder it is to bend. That's because while you are sliding layers of atoms back and forth, occasionally an atom (or an entire row of atoms) slips out of place. It is no longer part of a smooth layer, and so other atoms can't slide past it as easily. This situation is called a defect. Once there are enough defects in the metal, it is impossible to bend the material anymore. Metal atoms are found in organized layers. Because these layers can roll over each other, metals can be worked into different shapes.

3 0
2 years ago
CO(g) + 12 O2(g) → CO2(g)The combustion of carbon monoxide is represented by the equation above.(a) Determine the value of the s
devlian [24]

Answer : The standard enthalpy change for the combustion of CO(g) is, -283 kJ/mol

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The combustion of CO will be,

CO(g)+\frac{1}{2}O_2(g)\rightarrow CO_2(g)    \Delta H_{rxn}=?

The intermediate balanced chemical reaction will be,

(1) C(s)+\frac{1}{2}O_2(g)\rightarrow CO(g)     \Delta H_1=-110.5kJ/mol

(2) C(s)+O_2(g)\rightarrow CO_2(g)     \Delta H_2=-393.5kJ/mol

Now we are reversing reaction 1 and then adding both the equations, we get :

(1) CO(g)\rightarrow C(s)+\frac{1}{2}O_2(g)     \Delta H_1=110.5kJ/mol

(2) C(s)+O_2(g)\rightarrow CO_2(g)     \Delta H_2=-393.5kJ/mol

The expression for enthalpy change for the reaction will be,

\Delta H_{rxn}=\Delta H_1+\Delta H_2

\Delta H_{rxn}=(110.5)+(-393.5)

\Delta H_{rxn}=-283kJ/mol

Therefore, the standard enthalpy change for the combustion of CO(g) is, -283 kJ/mol

6 0
3 years ago
Question 10 of 10
Artist 52 [7]

Answer:

d 1 1/2 oz.. of 80-proof liquor

7 0
3 years ago
200mL of 4.98M of sodium chloride solution is added to an additional 532 ml of water what is the final molarity?
ELEN [110]

Answer:

M₂ = 1.9 M

Explanation:

Given data;

Volume of sodium chloride = 200 mL

Molarity of sodium chloride = 4.98 M

Volume of water = 532 mL

Final Molarity = ?

Solution:

M₁V₁ = M₂V₂

M₂ =  M₁V₁ /V₂

M₂ = 4.98 M × 200 mL / 532 mL

M₂ = 996 mL. M /532 mL

M₂ = 1.9 M

4 0
3 years ago
Use the Gizmo to estimate the age of each of the objects below. For these questions, each second in the Gizmo represents 1,000 y
ziro4ka [17]

Answer:

Check the explanation

Explanation:

AT = A0 e(-T/H)

... where A0 is the starting activity, AT is the activity at some time T, and H is the half-life, in units of T.

Substituting what we know, we get...

0.71 = (1) e(-T/5730)

Solve for T...

loge(0.71) = -T/5730

T = -loge(0.71)(5730)

T = 1962 (conservatively rounded, T = 2000)

similarly for all

for aboriginal charcoal

0.28 = (1) e(-T/5730)

Solve for T...

loge(0.28) = -T/5730

T = -loge(0.28)(5730)

T = 7294 (conservatively rounded, T = 7000)

for mayan headdress

0.89 = (1) e(-T/5730)

Solve for T...

loge(0.89) = -T/5730

T = -loge(0.89)(5730)

T = 667 (conservatively rounded, T = 700)

for neanderthal

0.05 = (1) e(-T/5730)

Solve for T...

loge(0.05) = -T/5730

T = -loge(0.05)(5730)

T = 17165 (conservatively rounded, T = 17000)

7 0
3 years ago
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