One term could be allostasis, the opposite of homeostasis.
Other antonyms of homeostasis, the body's ability to maintain a stable internal environment, include imbalance, instability, etc.
The volume of the 0.15 M LiOH solution required to react with 50 mL of 0.4 M HCOOH to the equivalence point is 133.3 mL
<h3>Balanced equation </h3>
HCOOH + LiOH —> HCOOLi + H₂O
From the balanced equation above,
The mole ratio of the acid, HCOOH (nA) = 1
The mole ratio of the base, LiOH (nB) = 1
<h3>How to determine the volume of LiOH </h3>
- Molarity of acid, HCOOH (Ma) = 0.4 M
- Volume of acid, HCOOH (Va) = 50 mL
- Molarity of base, LiOH (Mb) = 0.15 M
- Volume of base, LiOH (Vb) =?
MaVa / MbVb = nA / nB
(0.4 × 50) / (0.15 × Vb) = 1
20 / (0.15 × Vb) = 1
Cross multiply
0.15 × Vb = 20
Divide both side by 0.15
Vb = 20 / 0.15
Vb = 133.3 mL
Thus, the volume of the LiOH solution needed is 133.3 mL
Learn more about titration:
brainly.com/question/14356286
Answer:
t = 7.58 * 10¹⁹ seconds
Explanation:
First order rate constant is given as,
k = (2.303
/t) log [A₀]
/[Aₙ]
where [A₀] is the initial concentraion of the reactant; [Aₙ] is the concentration of the reactant at time, <em>t</em>
[A₀] = 615 calories;
[Aₙ] = 615 - 480 = 135 calories
k = 2.00 * 10⁻²⁰ sec⁻¹
substituting the values in the equation of the rate constant;
2.00 * 10⁻²⁰ sec⁻¹ = (2.303/t) log (615/135)
(2.00 * 10⁻²⁰ sec⁻¹) / log (615/135) = (2.303/t)
t = 2.303 / 3.037 * 10⁻²⁰
t = 7.58 * 10¹⁹ seconds
Answer:
a). Coordination no. of ![[Ni(en)_2(NH_3)_2]^2+](https://tex.z-dn.net/?f=%5BNi%28en%29_2%28NH_3%29_2%5D%5E2%2B)
= 6
b). Coordination no. of ![[Fe(en)(ox)Cl_2]^2-](https://tex.z-dn.net/?f=%5BFe%28en%29%28ox%29Cl_2%5D%5E2-)
= 6
Explanation:
Coordination number is defined as number of donar atoms bonded to the central atom of the complex ion.
a). Coordination no. of = 6
en or ethylenediamine is a bidentate ligand.
In bidentate ligand, two atoms directly bonded to the central atom.
NH3 is a unidentate ligand.
So, coordination no.= No. of bidentate ligand x 2 + No. of unidentate ligand
= 
b). Coordination no. of = 6
Ethylenediamine (en) is a bidentate ligand.
oxalate ion (ox) is also a bidentate ligand.
Cl is a unidentate ligand
So, coordination no.= No. of bidentate ligand x 2 + No. of unidentate ligand
=
The answer is either D or B. hope this helps.
