Graphite and diamond come under covalent structure.
Answer:
0.64 g O₂
Explanation:
I am assuming you meant 0.02 moles of O₂. In that case, convert moles to mass via stoichiometry:
0.02 mol O₂ x 32 g O₂/1 mol O₂ = 0.64 g O₂
Answer:
0.008 moles of gas are present
Explanation:
Given data:
Volume of gas = 1.75 L
Number of moles = ?
Temperature of gas = 58°C
Pressure of gas = 12.5 KPa
Solution:
The given problem will be solve by using general gas equation,
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
Now we will convert the temperature.
58+273 = 331 K
Pressure = 12.5/101 = 0.12 atm
by putting values in formula:
0.12 atm× 1.75 L = n× 0.0821 atm.L/ mol.K ×331 K
0.21 atm.L = n× 27.17atm.L/ mol
n = 0.21 atm.L /27.17atm.L/ mol
n = 0.008 mol
Answer:
The question is incomplete and confusing.
- In the complete ionic equation you write all the ions that are formed. Those are: Pb²⁺, NO₃⁻, K⁺, and I⁻. They all are present in the complete ionic equation.
- In the net ionic equation, the spectator ions do not appear. They are: NO₃⁻ and K⁺. They would not be present in the net ionic equation, but they do in the complete ionic equation.
See below the details.
Explanation:
Which compound will not form ions?
<u />
<u>1. Write the balanced molecular equation:</u>
- Pb(NO₃)₂(aq) + 2KI(aq) → PbI₂(s) + 2KNO₃(aq)
<u />
<u>2. Write the ionizations for the ionic aqueous compounds:</u>
<u />
- Pb(NO₃)₂(aq) → Pb⁺²(aq) + 2NO₃⁻(aq)
- 2KI(aq) → 2K⁺(aq) + 2I⁻(aq)
- 2KNO₃(aq) → 2K⁺(aq) + 2NO₃⁻(aq)
<u />
<u>3. Write the complete ionic equation:</u>
Pb⁺²(aq) + 2NO₃⁻(aq) + 2K⁺(aq) + 2I⁻(aq) → PbI₂(s) + 2K⁺(aq) + 2NO₃⁻(aq)
Hence, since PbI₂(s) does not ionize, but stays in solid form, it will not form ions.
All, Pb⁺², NO₃⁻, K⁺, and I⁻ will be present in the total ionic equation.
It is in the net ionic equation that the spectator ions are removed. Those, are NO₃⁻ and K⁺, because they are on both sides of the complete ionic equation.