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Gwar [14]
3 years ago
15

Pls I need help give away 11 points

Chemistry
1 answer:
Maru [420]3 years ago
7 0

Answer:

The charge is +2

Explanation:

Protons are positive, electrons are negative. 10-8=2.

+2 :)

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The temperature of a freezer started at 18şc. After cooling for a few hours, the freezer had a temperature of –12şc. What is the
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20 minus 2 plus 1 equals negative -2000000
8 0
3 years ago
a sample of solid is decomposed and found to contain 6.52g of potassium, 4.34 g of chromium and 5.34 of oxygen, what is the empi
Fynjy0 [20]

Answer:

K₂CrO₅

Explanation:

The empirical formula is the simplest formula of a compound. To find the empirical formula, we follow the procedure below:

Elements                         Potassium                 Chromium         Oxygen

Mass                                  6.52                             4.34                  5.34

Molar mass                          39                               60                      16

Number of moles             6.52/39                     4.34/60             5.34/16

                                             0.167                          0.072              0.333

Divide through by

the smallest                      0.167/0.072             0.072/0.072          0.333/0.072

                                            2.3                               1                                4.6

                                             2                                 1                                  5

Empirical formula K₂CrO₅

5 0
3 years ago
Hydrogen is diffusing through solid nickel. At a temperature of 358 K, the diffusivity is 1.16 x 10-8 cm2/s. At a temperature of
Lelu [443]

Answer:

Q_d=35881 J/mol

So the activation energy is 35881 J/mol.

Explanation:

Consider the following equations:

lnD_{1} =lnD_{o} -\frac{Q_{d} }{R*T_{1} }

lnD_{2} =lnD_{o} -\frac{Q_{d} }{R*T_{2} }

Solving the above two equation to find the Q_d in term of diffusivity and temperature we will get:

Q_{d}=-R*\frac{lnD_{1} -lnD_{2} }{\frac{1}{T_{1} }-\frac{1}{T_{2} }  }

where:

Q_d is the activation energy

D_1 is the diffusivity at T_1

D_2 is the diffusivity at T_2

Q_{d}=-8.31*\frac{ln1.16*10^-12 -ln1.05*10^-11 }{\frac{1}{358 }-\frac{1}{438 }  }

Q_d=35881 J/mol

So the activation energy is 35881 J/mol.

3 0
4 years ago
What is a limiting factor?
alukav5142 [94]
A limiting factor helps an organism outcompete other organisms i think that’s the answer
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3 years ago
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zavuch27 [327]

Explanation:

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4 0
3 years ago
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