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kolezko [41]
3 years ago
11

How many moles of Co2 will be produced if 9.0 moles of O2 completely react?

Chemistry
1 answer:
ale4655 [162]3 years ago
8 0
 <span>It depends on what was being combusted. 

Supposing the simplest case, where carbon is being burnt: 

C + O2 → CO2 

(9.0 mol O2) x (1 mol CO2 / 1 mol O2) = 9.0 mol CO2 

The answer would be different if the fuel contained any oxygen atoms, for example, alcohol.</span><span>
</span>
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About 55L of a gas in a flexible container is under a pressure of 3.2 atm and at a temperature of 520K. What is the new volume o
vampirchik [111]

Answer:

30.62 L

Explanation:

From the question given above, the following data were obtained:

Initial volume (V₁) = 55 L

Initial pressure (P₁) = 3.2 atm

Initial temperature (T₁) = 520 K

Final temperature (T₂) = 760 K

Final pressure (P₂) = 8.4 atm

Final volume (V₂) =?

The final volume of the gas can be obtained as follow:

P₁V₁ / T₁ = P₂V₂ / T₂

3.2 × 55 / 520 = 8.4 × V₂ / 760

176 / 520 = 8.4 × V₂ / 760

Cross multiply

520 × 8.4 × V₂ = 176 × 760

4368 × V₂ = 133760

Divide both side by 4368

V₂ = 133760 / 4368

V₂ = 30.62 L

Therefore, the new volume of the gas is 30.62 L

7 0
3 years ago
The image represents a(n)
Archy [21]

Answer:

B) atom of Xenon

Explanation:

Xenon is already stable alone, because it has a complete octet, or 8 electrons. This graph is not an ion because it shows xenon is its default state, consisting of 8 electrons.

It is not a molecule because a molecule is a group of atoms, or a compound, what is shown is a singular atom.

7 0
3 years ago
Read 2 more answers
A 1.59 mol sample of Kr has a volume of 641 mL. How many moles of Kr are in a 4.41 L sample at the same temperature and pressure
Marina86 [1]

Answer:

The correct answer is 10.939 mol ≅ 10.94 mol

Explanation:

According to Avogadro's gases law, the number of moles of an ideal gas (n) at constant pressure and temperature, is directly proportional to the volume (V).

For the initial gas (1), we have:

n₁= 1.59 mol

V₁= 641 mL= 0.641 L

For the final gas (2), we have:

V₂: 4.41 L

The relation between 1 and 2 is given by:

n₁/V₁ = n₂/V₂

We calculate n₂ as follows:

n₂= (n₁/V₁) x V₂ = (1.59 mol/0.641 L) x 4.41 L = 10.939 mol ≅ 10.94 mol

5 0
3 years ago
Can someone balance this chemical equation for me please : )
Gnoma [55]

Answer:

2

Explanation:

Tried out 1, but couldn't get whole numbers on the right side then, so went up to 2, worked

all four numbrrs: 2, 7, 4, 6

The 7 for oxygen got adjusted in the last step of the thinking, because it's the simplest to adjust.

since there are different prime numbers (or rather numbers that don't share prime factors) in the set, the numbers can't be revived by the same number and still give whole numbers as results (they can't be smaller)

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3 years ago
Why guys always coming at me for?
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You are beautiful just like me trust me i know<span />
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