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andrew11 [14]
3 years ago
6

In the function f(x) = 5(x2 − 4x + ____) + 15, what number belongs in the blank to complete the square? Numerical Answers Expect

ed!
Mathematics
2 answers:
Katyanochek1 [597]3 years ago
7 0
The number needed to complete the square is simply 4. 
Please mark me as brainliest.
sesenic [268]3 years ago
5 0

Answer:

4

Step-by-step explanation:

Given function is :

f(x) = 5(x² - 4x + _) +  15

We need to fill the gap.

In order to make complete the square, we will use the completing the square method.

Here we take the coefficient of x

that is -4

take half of -4 = -2

Now square the -2 = (-2)² = 4

add and subtract the 4

So, 4 belongs in the blank to complete the square.

That's the final answer.

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It travels for 2 hours, then stops for 1 hour, and finally travels again for 5 hours.

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How to solve this problem im not getting a good answer
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The vendor of a coffee cart mixes coffee beans that cost $9 per pound with coffee beans that cost $5 per pound. How many pounds
lidiya [134]

Answer:

56.25 pound of the coffee that costs $5 per pound is needed

18.75 pound of the coffee that costs $9 per pound is needed

Step-by-step explanation:

Let the number of pounds be x and y respectively

The total pounds is 75;

So;

x + y. = 75 •••••••(i)

Total cost of first type

9 * x = $9x

Total cost of second type;

5 * y= $5y

75 pound at $6 per pound; total cost of this is;

6 * 75 = $450

Thus;

9x + 5y = 450 ••••••••(ii)

From i, x = 75-y

Put this into ii

9(75-y) + 5y = 450

675 -9y + 5y = 450

4y = 675-450

4y = 225

y = 225/4

y = 56.25

x = 75 - y from i

x = 75-56.25

x = $18.75

8 0
3 years ago
A right-angled triangle has shorter side lengths exactly c^2-b^2 and 2bc units respectively, where b and c are positive real num
yKpoI14uk [10]

Answer: hypotenuse = c^{2} + b^{2}

Step-by-step explanation: Pythagorean theorem states that square of hypotenuse (h) equals the sum of squares of each side (s_{1},s_{2}) of the right triangle, .i.e.:

h^{2} = s_{1}^{2} + s_{2}^{2}

In this question:

s_{1} = c^{2}-b^{2}

s_{2} = 2bc

Substituing and taking square root to find hypotenuse:

h=\sqrt{(c^{2}-b^{2})^{2}+(2bc)^{2}}

Calculating:

h=\sqrt{c^{4}+b^{4}-2b^{2}c^{2}+(4b^{2}c^{2})}

h=\sqrt{c^{4}+b^{4}+2b^{2}c^{2}}

c^{4}+b^{4}+2b^{2}c^{2} = (c^{2}+b^{2})^{2}, then:

h=\sqrt{(c^{2}+b^{2})^{2}}

h=(c^{2}+b^{2})

Hypotenuse for the right-angled triangle is h=(c^{2}+b^{2}) units

3 0
3 years ago
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