Let the ball is initially at point P1. Finally it reaches at point P2.( bottom most). Since only conservative force is acting on the ball throughout the motion, mechanical energy will be conserved. Therefore conserving energy from P1 to P2,
Initially ball is at rest(P1). So initial kinetic energy is 0. Let ball is at height h1 initially, so initial potential energy = mgh ( m= mass of the ball). At bottom most point (P2), potential energy of ball changes into kinetic energy. So final kinetic energy =1/2 mv^2. Final potential energy = 0. Equating energies at P1 and P2,
Mgh= 1/2 mv^2. Therefore, v= (2gh)^1/2. Since all the initial and final points are at same height, velocity will be same for all the paths(irrespective of the path taken by ball). So velocity will be same.
The question is missing, but I guess the problem is asking for the distance between the cliff and the source of the sound.
First of all, we need to calculate the speed of sound at temperature of
:
The sound wave travels from the original point to the cliff and then back again to the original point in a total time of t=4.60 s. If we call L the distance between the source of the sound wave and the cliff, we can write (since the wave moves by uniform motion):
where v is the speed of the wave, 2L is the total distance covered by the wave and t is the time. Re-arranging the formula, we can calculate L, the distance between the source of the sound and the cliff:
<u>Explanation:</u>
- Victor pretends he can speak French > Rising action.
- Victor gets his school schedule > Exposition.
- Victor tries to get Teresa's attention after homeroom and at lunch > Rising action.
- Teresa asks Victor if he will help her in French > Falling action.
- Victor checks out books to learn French and help Teresa > Climax
Explanation:
velocity of a freely falling body is given as
h= height and g= acc. due to gravity = 32ft/sec^2.
now, t secs the object at height of s feet its velocity
here u= initial velocity =0,
therefore,