All categories

3 years ago

Hii please help i’ll give brainliest if you give a correct answer please

Physics

1 answer:

rodikova [14]3 years ago

8 0

B they are equal and and act in opposite directions

You might be interested in

a girl pushes a cart to the left with a 100-N force. A boy pushes it to the right with a 50-N force. what is the net force exert

NNADVOKAT [17]

Answer:

50 to the left

Explanation:

150-100: 50 to the left

3 0

3 years ago

What is the proportionality constant between an object and<br> its acceleration by a given force?

labwork [276]

Answer:

The net force acting on an object is proportional to the acceleration of that object with respect to an inertial frame of reference. The constant of proportionality in this, Newton's second law, is the classical mass of the object.

Explanation:

5 0

3 years ago

A horizontal pipe 18.0 cm in diameter has a smooth reduction to a pipe 9.00 cm in diameter. If the pressure of the water in the

Rzqust [24]

Answer:

The rate of flow of water is 71.28 kg/s

Solution:

As per the question:

Diameter, d = 18.0 cm

Diameter, d' = 9.0 cm

Pressure in larger pipe, P = $9.40\times 10^{4}\ Pa$

Pressure in the smaller pipe, P' = $2.80\times 10^{4}\ Pa$

Now,

To calculate the rate of flow of water:

We know that:

Av = A'v'

where

A = Cross sectional area of larger pipe

A' = Cross sectional area of larger pipe

v = velocity of water in larger pipe

v' = velocity of water in larger pipe

Thus

$\pi \frac{d^{2}}{4}v = \pi \frac{d'^{2}}{4}v'$

$18^{2}v = 9^v'$

v' = 4v

Now,

By using Bernoulli's eqn:

$P + \frac{1}{2}\rho v^{2} + \rho gh = P' + \frac{1}{2}\rho v'^{2} + \rho gh'$

where

h = h'

$\rho = 10^{3}\ kg/m^{3}$

$9.40\times 10^{4} + \frac{1}{2}\rho v^{2} = 2.80\times 10^{4} + \frac{1}{2}\rho (4v)^{2}$

$6.6\times 10^{4} = \frac{1}{2}\rho 15v^{2}$

$v = \sqrt{\frac{2\times 6.6\times 10^{4}}{15\times 10^{3}}} = 8.8\ m/s$

Now, the rate of flow is given by:

$\frac{dm}{dt} = \frac{d}{dt}\rho Al = \rho Av$

$\frac{dm}{dt} = 10^{3}\times \pi (\frac{18}{2}\times 10^{- 2})^{2}\times 8.8 = 71.28\ kg/s$

3 0

3 years ago

Read 2 more answers

How did the work of Dmitri Mendeleev differ from that of John Newlands in the development of the periodic table?

Sonja [21]

B.

Both recognized that the elements have repeating properties but Mendeleev realized that there are elements yet to be discovered while Newlands tried to fit the known elements together.

3 0

3 years ago

Read 2 more answers

How will you relate the distance of the planets with their period of revolution

My name is Ann [436]

Answer:

${t}^{2} \alpha {r}^{2}$

In other words, the time period squared is directly proportional to the radius of their orbit cubed

Explanation:

By combing equations for gravitational force and centripetal force, you can create a formula for t or r.

Feel free to message me if you want more help

3 0

4 years ago