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qwelly [4]
3 years ago
8

_______ is another resource often found buried with oil deposits.

Chemistry
2 answers:
Volgvan3 years ago
7 0

Answer: It would be A. Natural Gas

diamong [38]3 years ago
3 0
The answer is A.) Natural gas. 
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For the oxidation-reduction reaction equation given here 4ga+p4 indicate how many electrons are transferred in the formation of
sergij07 [2.7K]
The reaction given is:

4Ga + P4 ---> 4GaP

The oxidation number of the reactants is zero, because they are pure elements.

The P in compounds may have oxidation states 3- or 5-. Gallium may only have oxidation state 3+.

Then, to be neutral in GaP the oxidation states are 3+ for Ga and 3- for P.

And the transference of electrons can be see in this oxidation - reduction equations:

Ga (0) - 3 e-    ----> Ga (3+)

P (0) + 3e- ---> P (3-)

So, for one formula unit, 3 electrons have been transfered from each Ga atom to P atom to form one GaP unit.

Answer: 3 electrons.
3 0
3 years ago
Here is a multiple choice I need help on:
Ivenika [448]
I'm pretty sure it's B because carbon atoms are in all living organisms. They can also be bonded in different varations.
3 0
3 years ago
When a solution of barium nitrate and a solution of copper (II) sulfate are mixed, a chemical reaction produces solid barium sul
Artemon [7]
The total mass of the products is 10.76 g + 204.44 g = 215.20 g.
The masses of all the reactants but one are known so,

215.20 g - 120.00 g - 8.15 g - 75.00 g = 12.05 g

12.05 g is the mass of the unweighed barium nitrate. 
8 0
3 years ago
Read 2 more answers
In the reaction Ca + Cl2 → CaCl2, what is the mole ratio of chlorine to calcium chloride?
Anit [1.1K]

Answer:

D. 1:1

Explanation:

For every 1 mole of chlorine (Cl₂), there is one mole of calcium chloride (CaCl₂).

So, the mole ratio of chlorine to calcium chloride is 1:1.

Hope this helps. :)

6 0
3 years ago
Read 2 more answers
The incredible catalytic power of enzymes can perhaps best be appreciated by imagining how challenging life would be without jus
ioda

Answer:

t = 7.58 * 10¹⁹ seconds

Explanation:

First order rate constant is given as,

k =  (2.303 /t) log  [A₀] /[Aₙ]

where  [A₀]  is the initial concentraion of the reactant; [Aₙ] is the concentration of the reactant at time, <em>t</em>

[A₀]  = 615 calories;

[Aₙ] = 615 - 480 = 135 calories

k = 2.00 * 10⁻²⁰ sec⁻¹

substituting the values in the equation of the rate constant;

2.00 * 10⁻²⁰ sec⁻¹ = (2.303/t) log (615/135)

(2.00 * 10⁻²⁰ sec⁻¹) / log (615/135) = (2.303/t)

t = 2.303 / 3.037 * 10⁻²⁰

t = 7.58 * 10¹⁹ seconds

8 0
3 years ago
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