It would be Violet because it has the shortest wave length, while red has the longest wave length so it comes out the least of the colors.
Mass of KCl= 1.08 g
<h3>Further explanation</h3>
Given
1 g of K₂CO₃
Required
Mass of KCl
Solution
Reaction
K₂CO₃ +2HCl ⇒ 2KCl +H₂O + CO₂
mol of K₂CO₃(MW=138 g/mol) :
= 1 g : 138 g/mol
= 0.00725
From the equation, mol ratio K₂CO₃ : KCl = 1 : 2, so mol KCl :
= 2/1 x mol K₂CO₃
= 2/1 x 0.00725
= 0.0145
Mass of KCl(MW=74.5 g/mol) :
= mol x MW
= 0.0145 x 74.5
= 1.08 g
According to the task, you are proveded with patial pressure of CO2 and graphite, and here is complete solution for the task :
At first you have to find n1 =moles of CO2 and n2 which are moles of C
<span>The you go :
</span>
![CO2(g) + C(s) \ \textless \ =\ \textgreater \ 2CO(g)](https://tex.z-dn.net/?f=CO2%28g%29%20%2B%20C%28s%29%20%5C%20%5Ctextless%20%5C%20%3D%5C%20%5Ctextgreater%20%5C%20%202CO%28g%29%20)
n1 n2 0
-x -x +2x
![n1-x n2-x 2x Kp=P^2 (CO)/Pco2](https://tex.z-dn.net/?f=%20n1-x%20n2-x%202x%20Kp%3DP%5E2%20%28CO%29%2FPco2%20)
After that you have to use the formula
![Kp=(2x)^2/n1-x](https://tex.z-dn.net/?f=%20Kp%3D%282x%29%5E2%2Fn1-x)
Then you have to solve x, and for that you have to use <span>RT/V
And to find total values:</span>
![P(total)=n(total)*R*T/V](https://tex.z-dn.net/?f=%20P%28total%29%3Dn%28total%29%2AR%2AT%2FV)
I am absolutely sure that this would be helpful for you.
Answer:
whah the other dude said :) also stay safe
Explanation: