X=4
Step 1: Simplify both sides of the equation.
1.5(x+4)-3=4.5(x-2)
(1.5)(x)+(1.5)(4)+ -3 =(4.5)(x)+(4.5)(-2)
(1.5x) + ( 6+-3) =4.5x - 9
(Combine like terms)
1.5x+3=4.5x-9
Step 2: Subtract 4.5x from both sides.
1.5x +3 -4.5x =4.5x=-9-4.5x-3x+3=-9
Step 3: Subtract 3 from both sides.
-3x+3-3=-9-3
-3x=12
Step 4: Divide both by -3
-3x/-3=-12/-3
X=4
Answer:
Since the slope of the line is (31/4 - 25/4) / (5/4 - 3/4) = 3 that means that for every 1 that x increases, y increases by 3 so an example could be 1 3/4 for x and 9 1/4 for y.
Answer:
Length = 3.84 feets (nearest hundredth)
Step-by-step explanation:
The length of section of wire can be obtyaiejd using the length of of a arc formular :
Length of arc = θ/360° * 2πr
Radius, r = 2.5 feets
Length of arc = (88/360) *2πr
Length of arc = (88/360) * 2π*2.5
Length of arc = 0.244444 * 15.707963
Length of arc = 3.8397
Length = 3.84 feets (nearest hundredth)
Answer:
Step-by-step explanation:
These come directly from my textbook, so I'm not sure if your teacher will accept this kind of work.
1. Angle construction:
Given an angle. construct an angle congruent to the given angle.
Given: Angle ABC
Construct: An angle congruent to angle ABC
Procedure:
1. Draw a ray. Label it ray RY.
2. Using B as center and any radius, draw an arc that intersects ray BA and ray BC. Label the points of intersection D and E, respectively.
3. Using R as center and the same radius as in Step 2, draw an arc intersecting ray RY. Label the arc XS, with S being the point where the arc intersects ray RY.
4. Using S as center and a radius equal to DE, draw an arc that intersects arc XS at a point Q.
5. Draw ray RQ.
Justification (for congruence): If you draw line segment DE and line segment QS, triangle DBE is congruent to triangle QRS (SSS postulate) Then angle QRS is congruent to angle ABC.
You can probably also Google videos if it's hard to imagine this. Sorry, construction is super hard to describe.
Answer:
x = - 3 and x = 1
Step-by-step explanation:
Given the rational expression
The denominator of the expression cannot be zero as this would make the expression undefined. Equating the denominator to zero and solving gives the values that x cannot be, that is
x² + 2x - 3 = 0 ← in standard form
(x + 3)(x - 1) = 0 ← in factored form
Equate each factor to zero and solve for x
x + 3 = 0 ⇒ x = - 3
x - 1 = 0 ⇒ x = 1
Thus x = 1 and x = - 3 are both excluded values
