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Amanda [17]
3 years ago
13

A 360 volt light bulb has a resistance of 9 ohms. What is the current?

Physics
1 answer:
aleksklad [387]3 years ago
4 0

Answer:

here's the basis, I calculated everything you needed now you do your math to get the current.

Explanation:

Voltage (E) = Current (I) x Resistance (R)  

Power (watts) = Current Squared (I^2) x Resistance (R)  

Power = IxE = E^2 / R

my calculations:

Volts (E) =360

Amps (I)=40

Ohms (R)=9

Power (Watts)= 14400

hope this helps

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How fast did Newton decide a cannon ball shot out in order to escape Earth’s gravity?
arsen [322]

Plugging in for the Earth's mass and for G, we have 11.2 km/s for the escape velocity for an object launched from the Earth's surface. This is about 25,000 miles per hour

7 0
3 years ago
A Bicyclist that has a mass of 75 kg and is traveling at a velocity of 15 m/s would have how much kinetic energy ?
Marrrta [24]

Answer:

8437.5

Explanation:

By applying the formula of kinetic energy:

Kinetic energy=1/2 mv^2

5 0
3 years ago
How does the observed pitch of the buzzer change as it moves
andriy [413]

The answer is

Pitch of the buzzer increased (higher tone) as it moves towards the observer

5 0
3 years ago
un tanque de gasolina de 40 litros fue llenado por la noche, cuando la temperatura era de 68 grados farenheit. Al dia siguiente
Sedaia [141]

Answer:

Volume of gasoline that expands and spills out is 1.33 ltr

Explanation:

As we know that when temperature of the liquid is increased then its volume will expand and it is given as

\Delta V = V_o\gamma \Delta T

here we know that

V_o = 40 Ltr

volume expansion coefficient of the gasoline is given as

\gamma = 950 × 10^{–6}

change in temperature is given as

\Delta T = (131 - 68) \times \frac{5}{9}

\Delta T = 35 ^oC

Now we have

\Delta V = 40(950 \times 10^{-6})(35)

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3 0
4 years ago
on aircraft carriers, catapults are used to accelerate jet air craft to flight speeds in a short distance. One such catapult tak
sineoko [7]

Acceleration = (change in speed) / (time for the change)

Change in speed = (speed at the end) - (speed at the beginning)

The jet's change in speed = (70 m/s) - (zero) = 70 m/s

So acceleration = (70 m/s) / (2.5 s)

Acceleration = (70 / 2.5) m/s²

<em>Acceleration = 28 m/s²</em>  

That's about 2.9 G's .  Jet pilots can endure a lot more than that, but maybe the catapult or the hook on the airplane can't.  Let's look a little closer:

F = m A (Newton #2)

The force on the airplane = (18,000 kg) x (28 m/s²)

Force on the airplane = 504,000 Newtons

That's about 113,000 pounds !  Maybe the part of the airplane that the catapult pushes on can't handle any more force than that.  Or maybe that's the most force the catapult can deliver.

Also, the REACTION force on the catapult is the same 113,000 pounds.  Maybe the hooks or the chains or the struts on the catapult can't handle any more force than that.

That's almost 57 tons for gosh sakes !  Maybe the DECK of the carrier can't handle more force than that, and that's why they can't launch the airplane with acceleration of more than 2.9 G's .

8 0
3 years ago
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