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yanalaym [24]
3 years ago
8

If the force of a golf club on a golf ball is 200 N forward, what will the force of the ball on the club be? A. 200 N forward B.

200 N backward C. 400 N forward D. 400 N backward
Physics
2 answers:
Korolek [52]3 years ago
8 0

The ball should put 200 N of force towards the golfer.

Newton's Third Law is every action has an equal and opposite reaction.

It's the ball exerting 200 N of force towards the club as well, but the opposite reaction is that it flies away.

iren [92.7K]3 years ago
3 0

Explanation :

According to Newton's third law of motion, every action has an equal and opposite reaction.

If the force of a golf club on a golf ball is 200 N forward, then the force of the ball on the club will be same as 200 N. But this force will act in opposite direction i.e. backward.

So, the correct option is (B) i.e. 200 N backward.

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Friction removes energy from objects in motion. Which statement best describes how this works?
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<em>friction transforms KE into thermal energy (a)</em>

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Suppose an oven's radiation wavelength is 0.125 m. a container with 350.00 g of water was placed in the oven, and the temperatur
ivann1987 [24]
The heat (energy) needed to raise the temperature of the water is given by
Q=m C_S (T_f - T_i)=(350.0 g)(4.18 J/gC)(80C-20C)=87780 J

The wavelength of the radiation of the oven is \lambda=0.125 m, so the energy of a single photon of this radiation is
E=h \frac{c}{\lambda}=(6.6 \cdot 10^{-34}J) \frac{3\cdot 10^8 m/s}{0.125 m}=1.6 \cdot 10^{-24} J

So, the number of photons required to heat the water is the total energy absorbed by the water divided by the energy of a single photon:
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2 years ago
10. A 90 kg box is sliding across a surface at a constant velocity while experiencing a rightward applied
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If the box is moving at constant velocity, net force must be zero, so:

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4 0
3 years ago
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An empty graduated cylinder weighs 55.26 g. When filled with 48.1 mL of an unknown liquid, it weighs 92.39 g. The density of the
katrin [286]
<h2>Density of the unknown liquid is 771.93 kg/m³</h2>

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Weight of liquid = 0.09239 - 0.05526

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5 0
3 years ago
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THE GASEOUS STATE
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R  L atm mol^-1 K^-1
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pv = rt

divide both sides by v
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answer: p = rt/v




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For Ideal Gasses:


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P_ A/P_ total = n_ A RTV/n_ total RTV


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Therefore, P_ A = X_ A P_ total.



PV = nRT


P pressure

V volume


n Number of moles


R Gas Constant


T temperture (Kelvin.).







Hope that helps!!!!!! Have a great day : )

4 0
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