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morpeh [17]
3 years ago
10

Once the torch is lit why must the acetylene flow be increased until the flame stops smoking

Chemistry
1 answer:
mojhsa [17]3 years ago
5 0
Once the torch is lit, the acetylene flow must be increased until the flame stops smoking <span>before the oxygen is turned on for adjustment in order to keep the tip of the torch cool.

You should also note that while lighting the torch, you should keep the spark lighter near the tip but not covering it.</span>
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Please explainnnnnnnnnn
zysi [14]
The answer is 15g
The mass of a substance when given the density and volume can be found by using the formula
Mass = Density x Volume
From the question
Density of chloroform=1.5 g/ml
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5 0
2 years ago
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Points)<br> Determine the molar mass of NaCl (the solute) in a 0.1M aqueous solution of NaCl
nalin [4]

Answer:

  58.443 g/mol

Explanation:

The molar mass of NaCl is the sum of the molar masses of the individual atoms:

  Na: 22.989770 g/mol

  Cl: 35.453 g/mol

The total molar mass is ...

  NaCl: 58.443 g/mol

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The molar mass does not depend on whether the material is in solution or in any other form.

4 0
3 years ago
How might the government make sure scientific research is done in an ethical<br> way?
Lana71 [14]

Answer:

By taking away research funds if certain standards ar not met

Explanation:

3 0
3 years ago
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Which state of matter has a constant volume, but changes shape?\?
never [62]
Liquids stays the same volume but the bonds are spaced out enough that it can take the shape of whatever container it’s in.
8 0
3 years ago
In which of the following compounds does the carbonyl stretch in the IR spectrum occur at the lowest wavenumber?
klio [65]

Answer:

a. Cyclohexanone

Explanation:

The principle of IR technique is based on the <u>vibration of the bonds</u> by using the energy that is in this region of the electromagnetic spectrum. For each bond, there is <em>a specific energy that generates a specific vibration</em>. In this case, you want to study the vibration that is given in the carbonyl group C=O. Which is located around 1700 cm-1.

Now, we must remember that the <u>lower the wavenumber we will have less energy</u>. So, what we should look for in these molecules, is a carbonyl group in which less energy is needed to vibrate since we look for the molecule with a smaller wavenumber.

If we look at the structure of all the molecules we will find that in the last three we have <u>heteroatoms</u> (atoms different to carbon I hydrogen) on the right side of the carbonyl group. These atoms allow the production of <u>resonance structures</u> which makes the molecule more stable. If the molecule is more stable we will need more energy to make it vibrate and therefore greater wavenumbers.

The molecule that fulfills this condition is the <u>cyclohexanone.</u>

See figure 1

I hope it helps!

4 0
3 years ago
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