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anastassius [24]
3 years ago
15

How is the atomic mass of an element calculated?

Chemistry
1 answer:
zloy xaker [14]3 years ago
6 0

Answer:

Mass number (A) is the number of nucleons (proton and neutron) present in a atom.

Explanation:

electrons don't cout since they are thousandth's of the mass of protons or neutrons

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Combustion reactions are ones that always include elemental oxygen as a reactant. When a hydrocarbon (substance made up of carbo
inysia [295]

1. CH4 + 2O2 = CO2 + 2H20                 B.

2. 2CH2H6 + 7O2 = 4CO2 + 6H20      A  

3. C3H8 + 502 = 3CO2 + 4H20            C

<h3>
How to determine the appropriate products of reaction</h3>

To find the appropriate end products, use the following rules

  • The hydrogen ratio should be the same on both the product and reactant sides
  • The oxygen ratio should be the same on both the product and reactant sides
  • The carbon ratio should be the same on both sides.

Thus for equation;

1. CH4 + 2O2 = CO2 + 2H20                 B.

2. 2CH2H6 + 2O2 = 4CO2 + 6H20      A  

3. C2H8 + 502 = 2CO2 + 4H20            C  

Learn more about balancing equations here:

brainly.com/question/26694427

#SPJ1

5 0
2 years ago
If the volume is decreased from 5.15L to
hichkok12 [17]

Answer:

Increase

Explanation:

Boyle's law states volume and pressure have an inverse relationship.

- Hope that helped! Let me know if you need further explanation.

3 0
4 years ago
The standard cell potential Ec for the reduction of silver ions with elemental copper is 0.46V at 25 degrees celsius. calculate
Cloud [144]

Answer : The \Delta G for this reaction is, -88780 J/mole.

Solution :

The balanced cell reaction will be,  

Cu(s)+2Ag^+(aq)\rightarrow Cu^{2+}(aq)+2Ag(s)

Here, magnesium (Cu) undergoes oxidation by loss of electrons, thus act as anode. silver (Ag) undergoes reduction by gain of electrons and thus act as cathode.

The half oxidation-reduction reaction will be :

Oxidation : Cu\rightarrow Cu^{2+}+2e^-

Reduction : 2Ag^++2e^-\rightarrow 2Ag

Now we have to calculate the Gibbs free energy.

Formula used :

\Delta G^o=-nFE^o

where,

\Delta G^o = Gibbs free energy = ?

n = number of electrons to balance the reaction = 2

F = Faraday constant = 96500 C/mole

E^o = standard e.m.f of cell = 0.46 V

Now put all the given values in this formula, we get the Gibbs free energy.

\Delta G^o=-(2\times 96500\times 0.46)=-88780J/mole

Therefore, the \Delta G for this reaction is, -88780 J/mole.

7 0
4 years ago
Plz help me<br> thank you
Yakvenalex [24]
A. 4 mm.......0.5 mm
B. 1.5 mm......same size
6 0
3 years ago
At standard pressure, which element has a freezing point below standard temperature?
borishaifa [10]
⛄ (4)HG
-This is because it has a freezing point below standard temperature. 

5 0
4 years ago
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