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andrezito [222]
3 years ago
8

A 20kg mass approaches a spring at a speed of 30 m/s. The mass compresses the spring 12cm before coming to a stop. Calculate the

spring constant k of the spring (N/m). A. 150 kN/m B. 41.7 kN/m C. 125 N/m D. 1.25 MN/m
Physics
1 answer:
Oksana_A [137]3 years ago
5 0

Answer:

625000 N/ m

Explanation:

m= 20 kg

v= 30 m/s

x= 12 cm

k = ?

Here when the mass when hits at spring its speed is

Vi= 30 m/s

Finally it comes to rest after compressing for 12 cm

i-e Vf = 0 m/s

Distance= S= 12 cm = 0.12 m

using

2aS= Vf2 - Vi2

==> 2a ×0.12 = o- 30 × 30

==> a = 900 ÷ 0.24 = 3750 m/sec2

Now we know;

F = ma

F= -Kx

==> ma= -kx

==> 20 × 3750 = -K × 0.12

==> k = 625000 N/ m

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Explanation:

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L_{f}-L_{0}=\alpha L_{0}(T_{f}-T_{0})

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