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OlgaM077 [116]
3 years ago
5

Calculate the diffraction limit of the human eye, assuming a wide-open pupil so that your eye acts like a lens with diameter 0.8

centimeter, for visible light of 500-nanometer wavelength.
Physics
1 answer:
guapka [62]3 years ago
6 0
Hi, thank you for posting your question here at Brainly.

This problem could be solved using this equation:

Diffraction limit = 1.22*wavelength/diameter

diameter = 0.8 cm = 0.008 m
wavelength = 500E-9 m

Diffraction limit = 1.22(500E-9)/0.008
Diffraction limit = 0.00007625
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As shown in the figure below, a bullet is fired at and passes through a piece of target paper suspended by a massless string. Th
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Answer:

M = 0.730*m

V = 0.663*v

Explanation:

Data Given:

v_{bullet, initial} = v\\v_{bullet, final} = 0.516*v\\v_{paper, initial} = 0\\v_{paper, final} = V\\mass_{bullet} = m\\mass_{paper} = M\\Loss Ek = 0.413 Ek

Conservation of Momentum:

P_{initial} = P_{final}\\m*v_{i} = m*0.516v_{i} + M*V\\0.484m*v_{i} = M*V .... Eq1

Energy Balance:

\frac{1}{2}*m*v^2_{i} = \frac{1}{2}*m*(0.516v_{i})^2 + \frac{1}{2}*M*V^2 + 0.413*\frac{1}{2}*m*v^2_{i}\\\\0.320744*m*v^2_{i} = M*V^2\\\\M = \frac{0.320744*m*v^2_{i} }{V^2}  ....... Eq 2

Substitute Eq 2 into Eq 1

0.484*m*v_{i} = \frac{0.320744*m*v^2_{i} }{V^2} *V  \\0.484 = 0.320744*\frac{v_{i} }{V} \\\\V = 0.663*v_{i}

Using Eq 1

0.484m*v_{i} = M* 0.663v_{i}\\\\M = 0.730*m

7 0
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What is the scientific meaning of energy?
JulijaS [17]

Answer:

it is B

Explanation:

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When a high-energy proton or pion traveling near the speed of light collides with a nucleus, it may travel 2.5 x 10-15 m before
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Explanation:

It is given that,

When a high-energy proton or pion traveling near the speed of light collides with a nucleus, d=2.5\times 10^{-15}\ m

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Let t is the time interval required for the strong interaction to occur. The speed is given by :

c=\dfrac{d}{t}

t=\dfrac{d}{c}

t=\dfrac{2.5\times 10^{-15}\ m}{3\times 10^{8}\ m/s}

t=8.33\times 10^{-24}\ s

So, the time interval required for the strong interaction to occur is 8.33\times 10^{-24}\ s. Hence, this is the required solution.

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What is water that flows across eatlrtus surface
ira [324]

Water that flows across the surface is called a;

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The pirate ship tie at the amusement park is a giant pendulum that riders sit in. It swings back and forth, with a maximum veloc
kkurt [141]

Here as we know that there is no loss of energy

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now from above equation we have

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