Answer:
No one is right
Explanation:
John Case:
The function
is defined between -1 and 1, So it is not possible obtain a value
greater.
In addition, if you move the function cosine a T Value, and T is the Period, the function take the same value due to the cosine is a periodic function.
Larry case:
Is you have
, the domain of this is [0,2].
it is equivalent to adding 1 to the domain of the
, and its mean that the function
, in general, is not greater than
.
Answer:
The near point is 
Explanation:
From the question we are told that
The power is 
The distance from the eye is 
The distance of the book from the eye is 
Generally the focal length of the glasses is

=> 
=> 
=> 
The object distance is evaluated as

=> 
=> 
The image distance is evaluated from lens formula as

=> 
=> 
=> 
The near point is evaluated as

=> 
=> 
For three moles of an ideal gas are taken around the eye, the total work for the cycle is mathematically given as
Wt=1945.475J
<h3>What is the total work F for the cycle.(R=8.31J/molK)?</h3>
Generally, the equation for work is mathematically given as
Wt=wac+Wc+Wba
Therefore
Wac=Pa(Vc-Va)=nR(Tc-Ta)
Wac=3(8.314*192)
Wac=4788.864J
Wcb=P1v1-p2v2/v-1
Wcb-3*8.34*108/0.4
Wcb=-6734.34J
Wab=0
In conclusion,
Wt=wac+Wc+Wba
Wt=4788.864J+0+(-6734.34J)
Wt=+1945.475J
Read more about work
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Answer:
There is a localization of negative charge near the door handle.
Answer:
Q = 47.06 degrees
Explanation:
Given:
- The transmitted intensity I = 0.464 I_o
- Incident Intensity I = I_o
Find:
What angle should the principle axis make with respect to the incident polarization
Solution:
- The relation of transmitted Intensity I to to the incident intensity I_o on a plane paper with its principle axis is given by:
I = I_o * cos^2 (Q)
- Where Q is the angle between the Incident polarized Light and its angle with the principle axis. Hence, Using the relation given above:
Q = cos ^-1 (sqrt (I / I_o))
- Plug the values in:
Q = cos^-1 ( sqrt (0.464))
Q = cos^-1 (0.6811754546)
Q = 47.06 degrees