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Ann [662]
3 years ago
12

17. A 60.-kilogram student climbs a ladder a vertical distance of 4.0 meters in 8.0 seconds. Approximately how much total work i

s done against gravity by the student during the climb?
Physics
1 answer:
Margarita [4]3 years ago
8 0
Work done = change in PE = mgh = 60*10*4 = 2400 J
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Answer:

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Explanation:

Using as convention:

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The x- and y- components of the initial velocity of the jet can be written as

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While the components of the velocity of the wind are

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So the components of the resultant velocity of the jet are

v_x = v_{1x}+v_{2x}=406+548.6=954.6 mph\\v_y = v_{1y}+v_{2y}=0+147.0=147.0 mph

And the new speed is the magnitude of the resultant velocity:

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Explanation:

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Gemiola [76]

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