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DaniilM [7]
3 years ago
7

A store offers packing and mailing services to customers. The cost of shipping a box is a combination of a flat packing fee

Mathematics
2 answers:
shtirl [24]3 years ago
5 0

Answer:

f(x) = 2.25x + 5 or A

Step-by-step explanation:

Elanso [62]3 years ago
4 0

Answer:

f(x) = 2.25x + 5 is the answer

Step-by-step explanation:

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How to change base of logarithms: Best answer gets 27 points and brainliest answer
AlekseyPX

Answer:

1/3

Step-by-step explanation:

 To change from one base to another, we use the formula

Logb x = Loga x/Loga b

log1/9  (3^(1/3) /3)


log3 ((3^(1/3) /3))

-------------------------

log3 (1/9)


Log a /b = log a - log b

and 1/9 = 3^-2

log3 ((3^(1/3) ) - log3 (3)

-------------------------

log3 (3^-2)


log a^b  = blog a


1/3 log3 (3 ) - log3 (3)

-------------------------

-2log3 (3)

We know log3 (3) =1


1/3 (1) - 1

-------------------------

-2 (1)


1/3  - 1

-------------------------

-2


-2/3

------

-2

Copy dot flip

-2/3 * -1/2


1/3

6 0
3 years ago
Find the area of the shaded region. Round your answer to the nearest tenth.
Alex
Check the picture below on the left-side.

we know the central angle of the "empty" area is 120°, however the legs coming from the center of the circle, namely the radius, are always 6, therefore the legs stemming from the 120° angle, are both 6, making that triangle an isosceles.

now, using the "inscribed angle" theorem, check the picture on the right-side, we know that the inscribed angle there, in red, is 30°, that means the intercepted arc is twice as much, thus 60°, and since arcs get their angle measurement from the central angle they're in, the central angle making up that arc is also 60°, as in the picture.

so, the shaded area is really just the area of that circle's "sector" with 60°, PLUS the area of the circle's "segment" with 120°.

\bf \textit{area of a sector of a circle}\\\\
A_x=\cfrac{\theta \pi r^2}{360}\quad 
\begin{cases}
r=radius\\
\theta =angle~in\\
\qquad degrees\\
------\\
r=6\\
\theta =60
\end{cases}\implies A_x=\cfrac{60\cdot \pi \cdot 6^2}{360}\implies \boxed{A_x=6\pi} \\\\
-------------------------------\\\\

\bf \textit{area of a segment of a circle}\\\\
A_y=\cfrac{r^2}{2}\left[\cfrac{\pi \theta }{180}~-~sin(\theta )  \right]
\begin{cases}
r=radius\\
\theta =angle~in\\
\qquad degrees\\
------\\
r=6\\
\theta =120
\end{cases}

\bf A_y=\cfrac{6^2}{2}\left[\cfrac{\pi\cdot 120 }{180}~-~sin(120^o )  \right]
\\\\\\
A_y=18\left[\cfrac{2\pi }{3}~-~\cfrac{\sqrt{3}}{2} \right]\implies \boxed{A_y=12\pi -9\sqrt{3}}\\\\
-------------------------------\\\\
\textit{shaded area}\qquad \stackrel{A_x}{6\pi }~~+~~\stackrel{A_y}{12\pi -9\sqrt{3}}\implies 18\pi -9\sqrt{3}

7 0
3 years ago
Find the distance between the points (-5, -10) and (2, 4).
Novay_Z [31]
Ok, so I used the equation Y2 (4) - Y1 (-10) over X2 (2) -X1 (-5).
4 - -10 is 14 since if a minus sign is before a negative number, it becomes positive.
Same goes for 2 - -5. It is 7 since the minus sign is before the negative number. Final answer is 14/7 which can be simpflied to 2/1 since 14 divided by 7 =2. So the distance is 14\7, or 2\1.
3 0
2 years ago
Read 2 more answers
Can Someone Explain? The Question Is In The Picture!​
Amiraneli [1.4K]

(256)^{\tfrac 14}\\\\=(4^4)^{\tfrac 14}\\\\=4^{\tfrac 44}\\\\=4^1 \\\\= 4\\\\\\27^{\tfrac 13}\\\\=(3^3)^{\tfrac 13}\\\\=3^{\tfrac 33} \\\\=3^1\\\\=3

8 0
2 years ago
Please help me gotta pass
Rudik [331]
Answer:

Y=59 Z=93

Explanation:

To find Z, you have to know the line is equal to 180 degrees. You then subtract 180-87=93 that’s how you get Z. Then with that you know that 34+Y is going to equal 93 because they are across from each other. I forgot what that property is called, but yeah. Then you subtract 93-34=59 there you go hope that helps :)
4 0
3 years ago
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