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vampirchik [111]
3 years ago
15

When 1 mole of H2(g) reacts with F2(g) to form HF(g) according to the following equation, 542 kJ of energy are evolved H2(g) + F

2(g2HF(g) Is this reaction endothermic or exothermic? What is the value of q? kJ When 1 mole of Fe203(s) reacts with H2(g) to form Fe(s) and H20(g) according to the following equation, 98.8 kJ of energy are absorbed Fe2O3(s) +3H2(g)^2Fe(s) + 3H2Og) Is this reaction endothermic or exothermic? What is the value of q? kJ
Chemistry
1 answer:
d1i1m1o1n [39]3 years ago
6 0

Answer:

Exothermic. q = -542 kJ

Endothermic. q = 98.8 kJ

Explanation:

<em>When 1 mole of H₂(g) reacts with F₂(g) to form HF(g) according to the following equation, 542 kJ of energy are evolved. </em>

<em>H₂(g) + F₂(g) ⇄ 2 HF(g) </em>

<em>Is this reaction endothermic or exothermic? What is the value of q?</em>

Since the heat is evolved, the reaction is exothermic. When the reaction is exothermic, q is negative, that is, q = -542 kJ.

<em>When 1 mole of Fe₂O₃(s) reacts with H₂(g) to form Fe(s) and H₂0(g) according to the following equation, 98.8 kJ of energy are absorbed</em>

<em>Fe₂O₃(s) + 3 H₂(g) ⇄ 2 Fe(s) + 3 H₂O(g) </em>

<em>Is this reaction endothermic or exothermic? What is the value of q?</em>

Since the heat is absorbed, the reaction is endothermic. When the reaction is endothermic, q is positive, that is, q = 98.8 kJ.

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<h3>KCl or NaF, which has a higher lattice energy?</h3>

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A gas with a volume of 250 mL at a temperature of 293K is heated to 324K. What is the new volume of the gas?
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The new volume of the gas is 276.45 mL.

Explanation:

Charles's law indicates that for a given sum of gas at constant pressure, as the temperature increases, the volume of the gas increases, and as the temperature decreases, the volume of the gas decreases.

Charles's law is a law that mathematically says that when the amount of gas and pressure are kept constant, the quotient that exists between the volume and the temperature will always have the same value:

\frac{V}{T} =k

Analyzing an initial state 1 and a final state 2, it is satisfied:

\frac{V1}{T1} =\frac{V2}{T2}

In this case:

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Replacing:

\frac{250 mL}{293 K} =\frac{V2}{324 K}

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V2= 276.45 mL

<em><u>The new volume of the gas is 276.45 mL.</u></em>

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