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Anni [7]
3 years ago
11

Help! I need a little help on faulty parallel structure

Chemistry
1 answer:
bazaltina [42]3 years ago
5 0

I think it’s no tbh

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An empty vial weighs 55.32 g.
ziro4ka [17]

The answer is: Volume of mercury = 9.63 cm^3.

Density (d) is defined as mass of substance divided by its volume. Thus, if mass and density are known, then Volume can be determined.

What is the formula of volume in terms of density?

  • Let mass of substance be 'm' and volume be 'V'. Thus, as per the definition of density, it is expressed as-

d =\frac{m}{V}

  • Thus, volume can be expressed as-

V = \frac{m}{d}

  • Now, mass of empty vial= 55.32 g and the mass of  (vial+ mercury) = 185.56 g.

Thus, mass of mercury =185.56\ g- 55.32\g = 130.24\ g

  • Thus, mass of mercury = 130.24 g and density of mercury =13.53\ g/cm^3. Its volume is calculated as-

V =\frac{130.24\ g}{13.53\ g/cm^3}  = 9.63\ cm^3

  • Hence, volume of mercury = 9.63 cm^3.

To learn more about Density and Volume, visit:

brainly.com/question/1028144

#SPJ4

7 0
1 year ago
The diagram shows heat energy being transferred as hot water rises to the top of the pot and cool water sinks to the bottom.
Orlov [11]
I think it would be insulation
7 0
3 years ago
A 62.6-gram piece of heated limestone is placed into 75.0 grams of water at 23.1°C. The limestone and the water come to a final
alekssr [168]

Answer:

208.7°C was the initial temperature of the limestone.

Explanation:

Heat lost by limestone will be equal to heat gained by the water

-Q_1=Q_2

Mass of limestone = m_1=62.6 g

Specific heat capacity of limestone = c_1=0.921 J/g^oC

Initial temperature of the limestone = T_1=?

Final temperature = T_2=T =  51.9°C

Q_1=m_1c_1\times (T-T_1)

Mass of water= m_2=75.0 g

Specific heat capacity of water= c_2=4.186 J/g^oC

Initial temperature of the water = T_3=23.1^oC

Final temperature of water = T_2=T =  51.9°C

Q_2=m_2c_2\times (T-T_3)

-Q_1=Q_2

-(m_1c_1\times (T-T_1))=m_2c_2\times (T-T_3)

On substituting all values:

-(62.6 g\times 0.921 J/g^oC\times (51.9^oC-T_1))=75.0 g\times 4.186 J/g^oC\times (51.9^oC-23.1^oC)

T_1=208.7^oC

208.7°C was the initial temperature of the limestone.

7 0
3 years ago
Can yall assist me with this lab? It is really screwing me up... No spam!! the only part that I need is the last page. I will ma
kenny6666 [7]

Answer:

What do you need help with?!

Explanation:

5 0
2 years ago
Drag each label to the correct image. Each label can be used more than once.
guajiro [1.7K]

1) Acidic - gastric juices pH 1, lemon juice pH 2.2, tomato juice pH 4.

2) Neutral - salt solution pH 7.

3) Alkaline - baking soda pH 9, bleach pH 13.

pH is a numeric scale used to specify the acidity or basicity of an aqueous solution.

When pH is less than seven (pH<7), solution is acidic.

When is equal seven (pH = 7), solution is neutral.  

When pH is greater than seven (pH > 7), solution is basic.

5 0
3 years ago
Read 2 more answers
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