Question

"35.0 g of silicon dioxide contains how many grams of oxygen? a. 32.0 b. 18.6 c. 1.88 d. 0.530"

Answer 1

Answer:

b. 18.6

Explanation:

Given that:-

Mass of silicon dioxide = 35.0 g

Molar mass of silicon dioxide = 60.08 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{35.0\ g}{60.08\ g/mol}$

$Moles= 0.58255\ mol$

From the formula, $SO_2$ 1 mole of sulfur dioxide contains 2 moles of oxygen

So,

0.58255 mole of sulfur dioxide contains 2*0.58255 moles of oxygen

moles of oxygen = 1.1651 moles

Molar mass of oxygen = 15.999 g/mol

Mass= Moles*Molar mass = $1.1651\times 15.999\ g$ = 18.6 g