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Svet_ta [14]
2 years ago
12

Help with all of these problems

Mathematics
1 answer:
katovenus [111]2 years ago
4 0
#1 is 163:) I hoped that helped
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Please help asap 30 pts
Sergio [31]

4w-2(1-w)=-38\qquad|\text{use distributive property}\\\\4w+(-2)(1)+(-2)(-w)=-38\\\\4w-2+2w=-38\qquad|\text{add 2 to both sides}\\\\4w+2w=-36\\\\6w=-36\qquad|\text{divide both sides by 6}\\\\\boxed{w=-6}

<h3>Answer: d. w = -6</h3>
4 0
3 years ago
What is the solution to this system of equations?
Ede4ka [16]

Answer:

First choice.

Step-by-step explanation:

You could plug in the choices to see which would make all the 3 equations true.

Let's start with (x=2,y=-6,z=1):

2x+y-z=-3

2(2)+-6-1=-3

4-6-1=-3

-2-1=-3

-3=-3 is true so the first choice satisfies the first equation.

5x-2y+2z=24

5(2)-2(-6)+2(1)=24

10+12+2=24

24=24 is true so the first choice satisfies the second equation.

3x-z=5

3(2)-1=5

6-1=5

5=5 is true so the first choice satisfies the third equation.

We don't have to go any further since we found the solution.

---------Another way.

Multiply the first equation by 2 and add equation 1 and equation 2  together.

2(2x+y-z=-3)

4x+2y-2z=-6 is the first equation multiplied by 2.

5x-2y+2z=24

----------------------Add the equations together:

9x+0+0=18

9x=18

Divide both sides by 9:

x=18/9

x=2

Using the third equation along with x=2 we can find z.

3x-z=5 with x=2:

3(2)-z=5

6-z=5

Add z on both sides:

6=5+z

Subtract 5 on both sides:

1=z

Now using the first equation along with 2x+y-z=-3 with x=2 and z=1:

2(2)+y-1=-3

4+y-1=-3

3+y=-3

Subtract 3 on both sides:

y=-6

So the solution is (x=2,y=-6,z=1).

8 0
3 years ago
I NEED HELP PLEASE 15 POINTS
ra1l [238]

Answer:

20°

Step-by-step explanation:

∡EFJ = 70°

∡JFK = 90°

So, ∡KFG = 180 - ∡JFK - ∡EFJ = 180 - 90 - 70 = 20°

8 0
2 years ago
Pre cacl pleaseeeee help. the options are in the attachments as well
ivanzaharov [21]

Answer:

The values of x so that y = \csc x have vertical asymptotes are -2\pi, -\pi, 0, \pi, 2\pi.

Step-by-step explanation:

The function cosecant is the reciprocal of the function sine and vertical asymptotes are located at values of x so that function cosecant becomes undefined, that is, when function sine is zero, whose periodicity is \pi. Then, the  vertical asymptotes associated with function cosecant are located in the values of x of the form:

x = 0\pm \pi\cdot i, \forall \,i\in \mathbb{N}_{O}

In other words, the values of x so that y = \csc x have vertical asymptotes are -2\pi, -\pi, 0, \pi, 2\pi.

3 0
3 years ago
HELP ME PLEASE PLEASE IM BEGGING
suter [353]

Answer:

FALSE, (2, 9) is not a solution to the set of inequalities given.

Step-by-step explanation:

Simply replace x by 2 and y by 9 in the inequalities and see if the inequality is true or not:

irst inequality:

y\geq 4x\\9\geq 4\,(2)\\9\geq 8

so thi inequality is verified as true since 9 is larger or equal than 8

Now the second inequality:

y

This is FALSE since 9 is larger than 4 (not smaller)

Therefore the answer to the question is FALSE, (2, 9) is not a solution to the set of inequalities given.

6 0
3 years ago
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