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mart [117]
3 years ago
11

an object is placed at 0 on a number line.it moves 3 units to the right,then 4units to the left,and then 6 units to the right th

e displacement of the object is?
Chemistry
2 answers:
Soloha48 [4]3 years ago
8 0

The correct answer is: +5

Explanation:

An object is placed at 0; it means:

Initial position of the object = 0.

Now it moves to 3 units to right, so keeping the standard cartesian coordinate system in mind (in right right x-axis is positive and left x-axis is right), the new position of the object will be +3.

Object now moves 4 units to the left, it means +3 - 4 = -1; object is at the position -1.

Object then moves 6 units to the right, therefore,

Final position of the object = -1 + 6 = +5.

Displacement = Final position - Initial position

Displacement = +5 - 0 = The correct answer is: +5

Evgen [1.6K]3 years ago
4 0
It should probably be on a positive 5
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Huh what type of question is that?!
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Why is the energy supplied by the cooker greater than that calculated ?
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Answer:

Explanation:

Q1.

(a) 46 200

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Q2.

(a) (approximate same size particles as each other and as liquid and gas) touching

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[11]

Q3.

(a) x-axis labelled and suitable scale

Page 12 of 13

points plotted correctly

allow 5 correctly plotted for 2 marks, 3−4

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allow ecf from line of best fit in part (a)

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Q4.

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Page 13 of 13

(d) efficiency = 300/500

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7 0
2 years ago
When the reaction shown is correctly balanced, the coefficients are: kclo3 → kcl + o2?
notka56 [123]
From the balanced equation 2KClO3 → 2KCl + 3O2, the coefficients are the following:
coefficient 2 in front of potassium chlorate KClO3
coefficient 2 in front of potassium chloride KCl 
coefficient 3 in front of oxygen molecule O2

We got this balanced equation by identifying the number of atoms of each element that we have in the given equation KClO3 → KCl + O2.
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We can see that the oxygens are not balanced. We add a coefficient 2 to the 3 oxygen atoms on the left side and another coefficient 3 to the 2 oxygen 
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     2KClO3 → KCl + 3O2
The coefficient 2 in front of potassium chlorate KClO3 multiplied by the subscript 3 of the oxygen atoms on the left side indicates 6 oxygen atoms just as the coefficient 3 multiplied by the subscript 2 on the right side indicates 6 oxygen atoms.

The number of potassium K atoms and chloride Cl atoms have changed as well:
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We now have two potassium K atoms and two chloride Cl atoms on the reactant side, so we add a coefficient 2 to the potassium chloride KCl on the product side: 
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        K=2           K=2
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