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PSYCHO15rus [73]
3 years ago
15

Hydrogen iodide is not produced by the same method as for hydrogen chloride.why??

Chemistry
1 answer:
lara [203]3 years ago
4 0

Answer:

Using Phosphoric acid will work perfectly for producing Hydrogen halides because its not an Oxidizing agent. ...

Using an ionic chloride and Phosphoric acid

H3PO4 + NaCl ==> HCl + NaH2PO4

H3PO4 + NaI ==> HI + NaH2PO4

H2SO4 + NaCl ==> HCl + NaHSO4

This method(Using H2So4) will work for all hydrogen hydrogen halide except Hydrogen Iodide and Hydrogen Bromide.

The Sulphuric acid won't be useful for producing Hydrogen Iodide because its an OXIDIZING AGENT. Whist producing the Hydrogen Iodide... Some of the Iodide ions are oxidized to Iodine.

2I-² === I2 + 2e-

Explanation:

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Explanation:

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What is the final pH of a solution obtained by mixing 300 ml of 0.4 M NH3 with 175 ml of 0.3 M HCl? (Kb = 1.8 x 10-5) Show all o
MariettaO [177]

Answer:

pH of the final solution = 9.15

Explanation:

Equation of the reaction: HCl + NH₃ ----> NH₄Cl

Number of moles of  NH₃ = molarity * volume (L)

= 0.4 M * (300/1000) * 1 L =  0.12 moles

Number of moles of HCl =  molarity * volume (L)

= 0.3 M * (175/1000) * 1 L = 0.0525 moles

Since all he acid is used up in the reaction, number of moles of acid used up equals number of moles of NH₄Cl produced

Number moles of NH₄Cl produced =  0.0525 moles

Number of moles of base left unreacted =  0.12 - 0.0525 = 0.0675

pOH = pKb + log([salt]/[base])

pKb = -logKb

pOH = -log (1.8 * 10⁻⁵) + log (0.0525/0.06755)

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