That is false. A GPS cant tell latitude and longitude
Answer:
The value is 
Explanation:
From the question we are told that
The frequency of each sound is
The speed of the sounds is 
The distance of the first source from the point considered is 
The distance of the second source from the point considered is 
Generally the phase angle made by the first sound wave at the considered point is mathematically represented as
![\phi_a = 2 \pi [\frac{a}{\lambda} + ft]](https://tex.z-dn.net/?f=%5Cphi_a%20%3D%20%202%20%5Cpi%20%5B%5Cfrac%7Ba%7D%7B%5Clambda%7D%20%20%2B%20ft%5D)
Generally the phase angle made by the first sound wave at the considered point is mathematically represented as
Here b is the distance o f the first wave from the considered point
Gnerally the phase diffencence is mathematically represented as
=> ![\Delta \phi = \frac{2\pi [ a - b]}{ \lambda }](https://tex.z-dn.net/?f=%5CDelta%20%20%5Cphi%20%20%20%3D%20%20%20%5Cfrac%7B2%5Cpi%20%5B%20a%20-%20b%5D%7D%7B%20%5Clambda%20%7D)
Gnerally the wavelength is mathematically represented as

=> 
=> 
=> ![\Delta \phi = \frac{2* 3.142 [ 4.40 - 4.0 ]}{ 0.611 }](https://tex.z-dn.net/?f=%5CDelta%20%20%5Cphi%20%20%20%3D%20%20%20%5Cfrac%7B2%2A%203.142%20%5B%204.40%20-%204.0%20%5D%7D%7B%20%200.611%20%20%7D)
=> 
Answer:
a)0.0229 m
b)0.393 rad
c)1.57
d)707.6 N
e)0.298 m/s
Explanation:
Given:
- Mass of the machine, m=70 kg
- Stiffness of the system, k=30000 N/m
- Damping ratio=0.2
- Damping force, F=450 N
- Angular velocity

a)We know that the amplitude X at steady state is given by

Where
![X=\dfrac{\dfrac{450}{70}}{\sqrt{20.7^2-13^2)^2 +(2\times 0.2\times20.7\times13)^2}}\\[tex]X=0.0229\ \rm m](https://tex.z-dn.net/?f=X%3D%5Cdfrac%7B%5Cdfrac%7B450%7D%7B70%7D%7D%7B%5Csqrt%7B20.7%5E2-13%5E2%29%5E2%20%2B%282%5Ctimes%200.2%5Ctimes20.7%5Ctimes13%29%5E2%7D%7D%5C%5C%5Btex%5DX%3D0.0229%5C%20%5Crm%20m)
b) The phase shift of the motion is given by

c)Transmissibility ratio is given by

d)The magnitude of the force transmitted to the ground is

e)The maximum velocity is given by 

Gravitational force = Gxm1xm2 /r^2
This equation depends only upon object's masses and distance between them. So option b is correct
Answer:
a.work done=force *displacement
=500N*46m
=23000 Joule
b.power=work done/time taken
=23000/25
=920 watt
c.GPE=m*g*h(m=mass,g=gravity due to acceleration,h=height)
=60kg*9.8m/s*14m
=8232 joule
Explanation: