Question

A stonecutter's chisel has an edge area of 0.7 cm2. If the chisel is struck with a force of 42 N, what is the pressure exerted on the stone

Answer 1

Answer:

The pressure is $P = 583333 \ N/m^2$

Explanation:

From the question we are told that

  The area of the edge is  $A = 0.72 cm^2 = 0.72 *10^{-4}\ m$

    The  force is $F = 42 \ N$

The pressure is mathematically represented as

            $P = \frac{F}{A}$

substituting values

           $P = \frac{42}{0.72*10^{-4}}$

           $P = 583333 \ N/m^2$