Derive velocity-time relation from velocity-time graph

A cat’s crinkle ball toy of mass 15g is thrown straight up with an initial speed of 3m/s . Assume in this problem that air drag

Readme [11.4K]

Answer:

(a)0.0675 J

(b)0.0675 J

(c)0.0675 J

(d)0.0675 J

(e)-0.0675 J

(f)0.459 m

Explanation:

15g = 0.015 kg

(a) Kinetic energy as it leaves the hand

$E_k = \frac{mv^2}{2} = \frac{0.015*3^2}{2} = 0.0675 J$

(b) By the law of energy conservation, the work done by gravitational energy as it rises to its peak is the same as the kinetic energy as the ball leave the hand, which is 0.0675 J

(c) The change in potential energy would also be the same as 0.0675J in accordance with conservation law of energy.

(d) The gravitational energy at peak point would also be the same as 0.0675J

(e) In this case as the reference point is reversed, we would have to negate the original potential energy. So the potential energy as the ball leaves hand is -0.0675J

(f) Since at the maximum height the ball has potential energy of 0.0675J. This means:

mgh = 0.0675

0.015*9.81h = 0.0675

h = 0.459 m

The ball would reach a maximum height of 0.459 m

4 0

3 years ago

Recall that the blocks can only move along the x axis. the x components of their velocities at a certain moment are v1x and v2x.

Contact [7]

The center of mass is given with this formula:
$x_c=\frac{\sum_{n=1}^{n=i}m_ix_i}{M}$
Velocity is:
$v=\frac{dv}{dt}$
So, for the velocity of the center of mass we have:
$\frac{dx_c}{dt}=\frac{\sum_{n=1}^{n=i}d(m_ix_i)}{Mdt}\\
v_c=\frac{\sum_{n=1}^{n=i}p_i}{M}\\$
In our case it is:
$v_{xc}=\frac{m_1v_{x1}+m_2v_{x2}}{m_1+m_2}$

5 0

3 years ago

consider the mirror from the last question. an object 4cm tall stands 10cm in front of a converging mirror of focal length 5cm.

aleksandr82 [10.1K]

<span>An Object 4 Cm Tall Is Placed 12 Cm From A Divergi... | Chegg.com</span>

6 0

3 years ago

Read 2 more answers

Which of the following statements concerning the nuclear force is false? O The nuclear force is attractive and not repulsive. O

Ulleksa [173]

Answer:

The nuclear force is attractive and not repulsive.
The nuclear force is very weak and much smaller in relative magnitude than the electrostatic and gravitational forces.

Explanation:

Nuclear force is the strongest existing force in the nature.

It has the shortest range.

Its main function is to hold the subatomic particles together in nature.

The nuclear force is created by the exchange of pi mesons between the nucleons of an atom, but for this exchange to happen the particles must be close to one another of the order of few femtometer.

At about 1 femtometer the nuclear force is very strongly attractive in nature but at distance greater than 2.5 femtometer it fades away.

The force becomes repulsive in nature at distance less than 0.7 femtometer.
This force holds the likely charged protons together in the nucleus.

3 0

2 years ago

If it takes 50n of force to lift a 450n what is the ma of the machine

otez555 [7]

If the machine is 100% efficient, then its
Mechanical Advantage is (450/50) = 9 .

If the machine is less than 100% efficient,
then the MA is more than 9 .

7 0

3 years ago

Derive velocity-time relation from velocity-time graph ​

Derive velocity-time relation from velocity-time graph