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Alex Ar [27]
3 years ago
5

2. Using Graph 2, calculate the net force experienced by the particle between 4 and 6 seconds. The

Physics
1 answer:
Trava [24]3 years ago
3 0

Using Newtons Second Law:

F = m×a

F = (0.25 kg)(-2 m/s²)

F = -0.5 N

<h2>The correct option is C</h2>
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A lad, waiting for his friend walks in the sidewalk, in front of her house, from the front door, first, he moves towards the Pos
Andreas93 [3]

His total displacement from his original position is -1 m

We know that total displacement of an object from a position x to a position x', d = final position - initial position.

d = x' - x

If we assume the lad's initial position in front of her house is x = 0 m. The lad then moves towards the positive x-axis, 5 m. He then ends up at x' = 5 m. He then finally goes back 6 m.

Since displacement = final position - initial position, and his displacement is d' = -6 m (since he moves in the negative x - direction or moves back) from his initial position of x' = 5 m.

His final position, x" after moving back 6 m is gotten from

x" - x' = -6 m

x" = -6 + x'

x" = -6 + 5

x" = -1 m

Thus, his total displacement from his original position is

d = final position - initial position

d = x" - x

d = -1 m - 0 m

d = -1 m

So, his total displacement from his original position is -1 m

Learn more about displacement here:

brainly.com/question/17587058

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3 years ago
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All of the following are non-renewable resources except

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A sinusoidal wave travels along a stretched string. A particle on the string has a maximum speed of 2.0 m/s and a maximum accele
JulsSmile [24]

Answer:

The amplitude of the wave is 0.02 m.

Explanation:

Given that,

Maximum speed = 2.0 m/s

Maximum acceleration = 200 m/s²

We need to calculate the angular frequency

Using formula of angular frequency

\omega=\dfrac{a_{max}}{v_{max}}

Put the value into the formula

\omega=\dfrac{200}{2.0}

\omega=100\ rad/s

We need to calculate the amplitude of the wave

Using formula of velocity

v_{max}=A\omega

A=\dfrac{v_{max}}{\omega}

Put the value into the formula

A=\dfrac{2.0}{100}

A=0.02\ m

Hence, The amplitude of the wave is 0.02 m.

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