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irga5000 [103]
3 years ago
9

A binary star system consists of two stars of masses m1 and m2. The stars, which gravitationally attract each other, revolve aro

und the center of mass of the system. The star with mass m1 has a centripetal acceleration of magnitude a1.
Note that you do not need to understand universal gravitation to solve this problem.
Find a2, the magnitude of the centripetal acceleration of the star with mass m2. Express the acceleration in terms of quantities given in the problem introduction.
Physics
1 answer:
dusya [7]3 years ago
5 0

Answer:

Explanation:

According to the Newton's second law

Force  mass x acceleration

For the first star:

F = m_{1}a_{1}  .... (1)

According to Newton's third law, there is an equal and opposite force on star 2 due to star 1 which is equal to the F.

For second star:

F = m_{2}a_{2}    ..... (2)

By equation (1) and (2)

m_{1}a_{1} = m_{2}a_{2}

a_{2}=\frac{m_{1}a_{1}}{m_{2}}

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When discharging equivalent of 0% starting voltage will the capacitor reach after 5RC.

V(t) = V0e-t/RC = V0b initially.

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  • Capacitance refers to a capacitor's effect.
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<h3>What are the different types of capacitors?</h3>

The numerous kinds of capacitors and their applications.

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6 0
2 years ago
In a uranium fission reaction, uranium splits into two smaller atoms and energy. Where did the energy come from?
postnew [5]

Answer: C. Some of uranium's mass is converted into energy, so the smaller atoms have less mass.

Explanation:

From Einstein's mass-energy relation:

E = mc²

Mass and energy are equivalent. Mass can be converted into energy and energy into mass.

When Uranium atoms under go nuclear fission, smaller atoms are formed and huge amount of energy is released. This energy comes from the mass difference of the uranium nuclei and new nuclei formed. This mass converted into energy according to Einstein's equation.

7 0
3 years ago
Read 2 more answers
A giant wall clock with diameter d rests vertically on the floor. The minute hand sticks out from the face of the clock, and its
Katyanochek1 [597]

Answer:

d_{x}(t)=(D/2)cos(\frac{\pi}{30}*t)

Explanation:

We can try writing the equation of the horizontal component of the length of the minute hand in terms of distance and the angle, that depends of time in this particular case.

The x-component of the length of the minute hand is:

d_{x}(t)=dcos(\theta (t)) (1)

  • d is the length of the minute hand (d=D/2)
  • D is the diameter of the clock
  • t is the time (min)

Now, using the angular kinematic equations we can express the angle in term of angular velocity and time. As we know, the minute hand moves with a constant angular velocity, so we can use this equation:

\theta (t)=\omega *t (2)

Also we know, that the minute hand moves 90 degrees or π/2 rad in 15 min, so using the definition of angular velocity, we have:

\omega=\frac{\Delta \theta}{\Delta t}=\frac{\theta_{f}-\theta_{i}}{t_{f}-t{i}}=\frac{\pi/2-0}{15-0}=\frac{\pi}{30}

Now, let's put this value on (2)

\theta (t)=\frac{\pi}{30}*t

Finally the length x(t) of the shadow of the minute hand as a function of time t, will be:

d_{x}(t)=(D/2)cos(\frac{\pi}{30}*t)

I hope it helps you!

6 0
3 years ago
Children make toy telephones by sticking each end of a long string through a hole in the bottom of a paper cup and knotting it s
Darina [25.2K]

Answer:

The bottom of the cup passes the sound waves to the string, and so on to the other cup. You can hear surprisingly far using a string telephone if help the right way! If the string is kept tight, the sound waves will travel.

Explanation:

3 0
3 years ago
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Ilia_Sergeevich [38]
The mass of the object doesn't matter. The change in its momentum is equal to the impulse that changed it ... 15 N-sec.
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3 years ago
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