B. No, the rectangle cannot have x = 20 and y = 11 because x + y ≠ 32
Perimeter = 2(l + w)
Perimeter = 64
Assuming: P = 64; w = 11 ; l = ?
64 = 2(l + 11)
64/2 = l + 11
32 - 11 = l
length = 21.
Answer:
the secound ansewr
Step-by-step explanation:ik
Y - y1 = m (x + x1)
Solve for m by subtracting the y's and dividing them by the difference of the 2 x's.
-32 - 1 = -33
-8 - 3 = -11
Divide the two to get 3.
Use the first point (as instructed) and plug it into the equation.
y - (-32) = 3 (x - (-8))
y + [32] = [3] (x + [5])
The brackets are the fill in the blanks.
Answer:
y= -3/5x + 2
Step-by-step explanation: