Answer:
60 kg m/s
Explanation:
Let 
be the acceleration of the object.
As the acceleration of the object is constant, so
Given that applied force, F=6.00 N,
From Newton's second law, we have
,
[from equation (i)]
[given that time, t=10 s and F=6 N]
Here mv is the final momentum of the object and mu is the initial momentum of the object.
So, the change in the momentum of the object is mv-mu.
Hence, the change in the momentum of the object is 60 kg m/s.
Answer:
-scalar
Explanation:
-A scalar is any quantity that has a magnitude, but no direction
-quantities with no specified direction.
hope it helps:)
Answer:
5.9 cm
Explanation:
We'll begin by calculating the spring constant (K) of the spring. This can be obtained as follow:
Force (F) = 15 N
Extention (e) = 3 cm
Spring constant (K) =.?
F = Ke
15 = K × 3
Divide both side by 3
K = 15 / 3
K = 5 N/cm
Therefore, the spring constant (K) is 5 N/cm.
Now, we shall determine how far the spring will stretch when a 3 kg candy is placed on the spring balance.
This can be obtained as follow:
First, we shall determine the weight of the object.
Mass of object = 3 Kg
Acceleration due to gravity (g) = 9.8 m/s²
Weight (W) =?
W = mg
W = 3 × 9.8
W = 29.4 N
Finally, we shall determine how far the spring will stretch as follow:
Weight (W) = Force (F) = 29.4 N
Spring constant (K) = 5 N/cm
Extention (e) =?
F = ke
29.4 = 5 × e
Divide both side by 5
e = 29.4 / 5
e = 5.88 ≈ 5.9 cm
Therefore, the spring will stretch 5.9 cm when a 3 kg candy is placed on the spring balance.
