The zeros of f(x)= 3x^3+16x^2+18x-4
1 answer:
After trial and error, you discover that - 2 works.
-2 || 3 16 18 -4
-6 -20 4
====================================
3 10 - 2 0
What you have left is a quadratic
3x^2 + 10x - 2 You can just use the quadratic formula to solve for the other 2 roots.
x1 = [ - 10 +/- sqrt(10^2 - 4*3*(-2) ) ] / 6
x1 = [ -10 +/- sqrt (100 + 24) ) /6
x1 = [ - 10 +/- sqrt(124) ) / 6
x1 = [ - 10 +/- 11.14 ] / 6 = 0.1893
x2 = [ - 21.14 ] / 6 = - 3.522
Answer
x1 = - 2
x2 = 0.1893
x3 = - 3.522
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Answer: The minimum value of C is 46.
Step-by-step explanation:
Since, Here, We have to find out Min C = 7x+8y
Given the constraints are -------(1)
------------- (2)
,
-------- (3)
Since, For equation 1) x-intercept, (4, 0) and y-intercept (0,8)
And, ⇒
( false)
Therefore the area of line 1) does not contain the origin.
For equation 2) x-intercept, (6, 0) and y-intercept (0,6)
And, ⇒
( false)
Therefore the area of line 2) does not contain the origin.
Thus after plotting the constraints 1) 2) and 3) we get Open Shaded feasible region AEB ( Shown in below graph)
At A≡(0,8) , C= 64
At E≡(2,4), C= 46
At B≡(6,0), C= 42
Thus at B, C is minimum, And its minimum value = 42
