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3 years ago

8

I have my chemistry EOC tomorrow, and I need to know how to calculate the molar mass of a compound. Specifically ones set up lik

e Fe₃(PO₄)₂ with the parentheses

1 answer:

yuradex [85]3 years ago

6 0

Answer:

357.475

Explanation:

First you need periodic table and you have to look for mass

Fe = 3 x 55.845 = 167.535

P = 2 x 30.97 = 61.94

o = 4 x 2 so 8 oxygen = 8 x 16 = 128

add all and you get 357.475

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The diagram shows a plant cell.

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A 100 W light bulb is placed in a cylinder equipped with a moveable piston. The light bulb is turned on for 2.0×10−2 hour, and t

drek231 [11]

Answer:

(a) ΔU = 7.2x10²

(b) W = -5.1x10²

(c) q = 5.2x10²

Explanation:

From the definition of power (p), we have:

$p = \frac {\Delta W}{\Delta t} = \frac {\Delta U}{\Delta t}$ (1)

<em>where, p: is power (J/s = W (watt)) W: is work = ΔU (J) and t: is time (s) </em>

(a) We can calculate the energy (ΔU) using equation (1):

$\Delta U = p \cdot \Delta t = 100 \frac{J}{s} \cdot 2.0\cdot 10^{-2} h \cdot \frac{3600s}{1h} = 7.2 \cdot 10^{2} J$

(b) The work is related to pressure and volume by:

$\Delta W = -p \Delta V$

<em>where p: pressure and ΔV: change in volume = V final - V initial </em>

$\Delta W = - p \cdot (V_{fin} - V_{ini}) = - 1.0 atm (5.88L - 0.85L) = - 5.03 L \cdot atm \cdot \frac{101.33J}{1 L\cdot atm} = -5.1 \cdot 10^{2} J$

(c) By the definition of Energy, we can calculate q:

$\Delta U = \Delta W + \Delta q$

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I hope it helps you!

6 0

3 years ago

Which of the following substances contains exactly 6.02 x 1023 formula units of the given

aniked [119]

Answer:

your question is incomplete and its

$6.02 \times {10}^{23?}$

particles which is one mole of a substance

Explanation:

you can solve the question by using this formular 1 mole of a substance=mass of the substance/ its molar mass

you find molar mass of a compound by adding individual molar masses of elements in that compound

3 0

2 years ago

2.56 g of hydrogen reacts completely with 20.32 g of oxygen<br> to form X g of water. X = g

Brilliant_brown [7]

Answer:

Mass of water produced is 22.86 g.

Explanation:

Given data:

Mass of hydrogen = 2.56 g

Mass of oxygen = 20.32 g

Mass of water = ?

Solution:

Chemical equation:

2H₂ + O₂ → 2H₂O

Number of moles of oxygen:

Number of moles = mass/ molar mass

Number of moles = 20.32 g/ 32 g/mol

Number of moles = 0.635 mol

Number of moles of hydrogen:

Number of moles = mass/ molar mass

Number of moles = 2.56 g/ 2 g/mol

Number of moles = 1.28 mol

Now we will compare the moles of water with oxygen and hydrogen.

O₂ : H₂O

1 : 2

0.635 ; 2×0.635 = 1.27

H₂ : H₂O

2 : 2

1.28 : 1.28

The number of moles of water produced by oxygen are less thus it will be limiting reactant.

Mass of water produced:

Mass = number of moles × molar mass

Mass = 1.27 × 18 g/mol

Mass = 22.86 g

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