What type of chemical reaction is h2so4 + 2kohk2so4 + 2h2o

Draw the reactants using the drawing tool. Keep in mind that one molecule of nitrogen has two bonded atoms, and one molecule of

ANTONII [103]

The formation of ammonia gas involves reacting hydrogen gas and nitrogen gas in a mole ratio of 3 to 1. as shown below:

$N_2 + 3H_2 \rightarrow 2NH_3$

<h3>What is the equation of the formation of ammonia?</h3>

Ammonia gas is formed from the reaction between nitrogen gas and hydrogen gas.

Three moles of hydrogen gas will react with 1 mole of nitrogen gas to form 2 moles of ammonia gas.

The equation of the reaction is given below as:

$N_2 + 3H_2 \rightarrow 2NH_3$

Therefore, the formation of ammonia gas involves reacting hydrogen gas and nitrogen gas in a mole ratio of 3 to 1.

Learn more about ammonia gas at: brainly.com/question/7982628

5 0

2 years ago

Which type of radiation detection device uses a phosphor-coated surface to detect radiation?

andreev551 [17]

In the choices above, the correct letter of the question is letter a, scintillation counter. It is because it uses a phosphor-coated surface in order to use its function in detecting radiation. Its component could produce bright flashes where it will be sufficient in detecting the radiation.

4 0

3 years ago

An unknown substance has been shown to have metallic bonds.

gladu [14]

This is the correct answer please mark me as brainliest

6 0

3 years ago

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How many grams of h2 will be produced if 175g of HCI are allowed to react completely with sodium

Sedbober [7]

Answer:

4.8 grams of H₂ will be produced if 175g of HCI are allowed to react completely with sodium

Explanation:

By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction) you can see that the following amounts in moles of each compound react and are produced:

HCl: 2 moles
Na: 1 mole
NaCl: 2 moles
H₂: 1 mole

You know the following masses of each element:

H: 1 g/mole
Cl: 35.45 g/mole
Na: 23 g/mole

So, the molar mass of each compound participating in the reaction is:

HCl: 1 g/mole + 35.45 g/mole= 36.45 g/mole
Na: 23 g/mole
NaCl: 23 g/mole + 35.45 g/mole= 58.45 g/mole
H₂: 2* 1 g/mole= 2 g/mole

Then, by stoichiometry of the reaction, the following amounts in grams of each of the compounds participating in the reaction react and are produced:

HCl: 2 moles* 36.45 g/mole= 72.9 g
Na: 1 mole* 23 g/mole= 23 g
NaCl: 2 moles* 58.45 g/mole= 116.9 g
H₂: 1 mole* 2 g/mole= 2 g

So, a rule of three applies as follows: if by stoichiometry, when reacting 72.9 grams of HCl 2 grams of H₂ are formed, when reacting 175 grams of HCl how much mass of H₂ will be formed?

$mass of H_{2} =\frac{175 g of HCl*2g ofH_{2} }{72.9 g of HCl}$