Answer:
The final molarity of acetate anion in the solution is 0.0046 moles
Explanation:
The balanced equation is
Cu(C₂H₃O₂)₂ + Na₂CrO₄ = CuCrO₄ + 2Na(C₂H₃O₂)
Therefore one mole of Cu(C₂H₃O₂)₂ react with one mole of Na₂CrO₄ to form one mole of CuCrO₄ and two moles of Na(C₂H₃O₂)
Mass of copper (II) acetate present = 0.708 g
Volume of aqueous sodium present = 50 mL
Molarity of sodium chromate = 46.0 mM
Therefore
Number of moles of sodium chromate present = (50 mL/1000)×46/1000 = 0.0023 M
Number of moles of copper (II) acetate present = 181.63 g/mol
number of moles of copper (II) acetate present = (0.708 g/181.63 g/mol) =0.0039 moles
Therefore 0.0039 moles of Cu(C₂H₃O₂)₂ × (2 moles of Na(C₂H₃O₂))/1 Cu(C₂H₃O₂)₂) = 0.00779 moles of Na(C₂H₃O₂)
also 0.0023 moles of Na₂CrO₄ × (2 moles of Na(C₂H₃O₂))/1 Na₂CrO₄) = 0.0046 moles of Na(C₂H₃O₂)
Therefore the Na₂CrO₄ is the limiting reactant and 0.0046 moles of Na(C₂H₃O₂) or acetate anion is formed
Answer:
Because water is polar and oil is nonpolar, their molecules are not attracted to each other. ... Because water molecules are polar, they interact with the sodium and chloride ions. In general, polar solvents dissolve polar solutes, and nonpolar solvents dissolve nonpolar solutes.
Explanation:
hope i helps u
Answer:
1.40 moles.
Explanation:
The balanced chemical equation for the reaction of Phosphorus and Oxygen is as follows -
In Part A, the oxygen was taken in excess. So Phosphorus will be the limiting reagent.
Since, 2 moles of 
is formed by 4 moles of 
So, for 1.8 moles of amount of required moles of = 
In Part B, the phosphorus was taken in excess so oxygen will be the limiting reagent.
Since, 2 moles of is formed by 5 moles of oxygen
So, for 1.40 moles of moles of 
required = 
Thus as of now we have 3.60 moles of and 3.50 moles of .
As in the reaction of formation of , oxygen is the limiting reagent.
So the moles of formed by the 3.50 moles of oxygen will be
= 
= 1.40 moles.
I think the answer is b because that is true
Answer:
The density of the stone whose mass is 25 g and its volume is 5 mL is 5 g/mL.
We have a graduated cylinder holding a volume of water equal to 2 mL. After a stone is added, the height of the water rose to 7 mL. The volume of the stone is equal to the difference in the levels of water.
The stone has a volume of 5 mL and a mass of 25 g. Its density, that is the ratio of the mass to the volume, is:
The density of the stone whose mass is 25 g and its volume is 5 mL is 5 g/mL.The density of the stone is 5 g/cm³.
Mass = 25 g
Volume = 7 mL – 2 mL = 5 mL = 5 cm³
Density = mass/volume = 25 g/5 cm³ = 5 g/cm³
Explanation:
