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Oksana_A [137]
3 years ago
9

John wishes to pay off his car loan of $4,626 in 18 months. How much will his monthly payment be assuming he pays the same amoun

t every month?
Mathematics
1 answer:
nydimaria [60]3 years ago
3 0

Answer: $257 per month

Explanation:

Pay = monthly payment

Set the total cost equal to number of months times payment per month (which you would leave as a variable because that’s what you’re solving for).

4,626 = 18P

Divide both sides by 18 because you’re trying to isolate the P.

4,626 = 18P —-> 257 = Pr

This leaves you with an evenly split number of 257.

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1!+2(2!)+3(3!)+...+n(n!)=(n+1)!-1<br><br><br><br><br>​
anyanavicka [17]

Step-by-step explanation:

OK, let's assume it this way:

<em>Sn=1.1!+2.2!+3.3!+...+n.n!</em><em>=</em><em>(</em><em>2</em><em>‐</em><em>1</em><em>)</em><em>.</em><em>1</em><em>!</em><em>+</em><em>(</em><em>3</em><em>-</em><em>1</em><em>)</em><em>.</em><em>2</em><em>!</em><em>+</em><em>(</em><em>4</em><em>-</em><em>1</em><em>)</em><em>3</em><em>!</em><em>+</em><em>.</em><em>.</em><em>.</em><em>+</em><em>(</em><em>(</em><em>n</em><em>+</em><em>1</em><em>)</em><em>-</em><em>1</em><em>)</em><em>.</em><em>n</em><em>!</em>

Sn=1.1!+2.2!+3.3!+...+n.n!=(2‐1).1!+(3-1).2!+(4-1)3!+...+((n+1)-1).n!<em>=</em><em>(</em><em>2</em><em>.</em><em>1</em><em>!</em><em>-</em><em>1</em><em>!</em><em>)</em><em>+</em><em>(</em><em>3</em><em>.</em><em>2</em><em>!</em><em>-</em><em>2</em><em>!</em><em>)</em><em>+</em><em>(</em><em>4</em><em>.</em><em>3</em><em>!</em><em>-</em><em>3</em><em>!</em><em>)</em><em>+</em><em>.</em><em>.</em><em>.</em><em>+</em><em>(</em><em>(</em><em>n-1</em><em>)</em><em>n</em><em>!</em><em>-</em><em>n</em><em>!</em><em>)</em><em>=</em><em>(</em><em>2</em><em>!</em><em>-</em><em>1</em><em>!</em><em>)</em><em>+</em><em>(</em><em>3</em><em>!</em><em>-</em><em>2</em><em>!</em><em>)</em><em>+</em><em>(</em><em>4</em><em>!</em><em>-</em><em>3</em><em>!</em><em>)</em><em>+</em>

Sn=1.1!+2.2!+3.3!+...+n.n!=(2‐1).1!+(3-1).2!+(4-1)3!+...+((n+1)-1).n!=(2.1!-1!)+(3.2!-2!)+(4.3!-3!)+...+((n-1)n!-n!)=(2!-1!)+(3!-2!)+(4!-3!)+<em>.</em><em>.</em><em>.</em><em>+</em><em>(</em><em>n</em><em>+</em><em>1</em><em>)</em><em>!</em><em>-</em><em>n</em><em>!</em><em>=</em><em>(</em><em>n</em><em>+</em><em>1</em><em>)</em><em>!</em><em>-</em><em>1</em><em>!</em><em>=</em><em>(</em><em>n</em><em>+</em><em>1</em><em>)</em><em>!</em><em>-</em><em>1</em>

and boom problem solved

7 0
2 years ago
What is the scientific notation for 3800
BigorU [14]

3.8 x 10²

im pretty sure thats scientific notation

8 0
3 years ago
In an auditorium, a charity show is conducted in order to raise at least $3,750. The auditorium can accommodate up to 180 specta
Maksim231197 [3]

Answer:

See explanation

Step-by-step explanation:

Let x,\ x\ge 0 be the number of students and y,\ y\ge 0 be the number of adults on the show.

1. Tickets cost $15 for students, so x student tickets cost $15x.

Tickets cost $25 for adults, so y adult tickets cost $25y.

Total cost of all tickets is $(15x + 25y).

The charity show is conducted in order to raise at least $3,750, thus

15x+25y\ge 3,750

2. The auditorium can accommodate up to 180 spectators, hence

x+y\le 180

3. We get the system of inequalities:

\left\{\begin{array}{l}x\ge 0\\y\ge 0\\x+y\le 180\\15x+25y\ge 3,750\end{array}\right.

Plot all solutions sets to each inequality and the common region is the solution set to the system of inequalities. This region is not empty, so the charity will reach its goal. For example, if they sell 50 students tickets and 125 adult tickets, they will raise \$(15\cdot 50+25\cdot 125)=\$3,875

8 0
3 years ago
What is the unknown fraction? <br><br>6/10 + ____ = 62/100​
sergeinik [125]
The answer is 2/100 or 1/50!

6/10 is equivalent to 60/100.
62/100 - 60/100 = 2/100 = 1/50

So, 6/10 + 1/50 = 62/100
6/10 + 2/100 = 62/100

(Use 1/50 because that’s the simplified answer!)

I hope this made sense! Good luck!
4 0
2 years ago
Objects A and B are in harmonic motion modeled by
Zepler [3.9K]

Answer:

The phase difference between yA and yB is  \frac{-\pi }{12}

Step-by-step explanation:

Given harmonic modeled as :

yA = 8 sin(2t  - \frac{\pi }{3})         And

yB = 8 sin(2t  - \frac{\pi }{4})

The function as written as :

y = a sin(ωt  - Ф)  where  Ф is phase difference

So , phase difference between yA   and  yB = ( Ф_1 - Ф_2 )

Or phase difference between yA   and  yB = ( -  \frac{\pi }{3} + \frac{\pi }{4} )

Or, phase difference between yA   and  yB = (\frac{-4\pi +3\pi }{12})

I.e phase difference between yA   and  yB =\frac{-\pi }{12}

Hence The phase difference between yA and yB is \frac{-\pi }{12}   Answer

4 0
3 years ago
Read 2 more answers
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