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krok68 [10]
4 years ago
6

a trombone can be modeled like an open closed air tube. the trombone plays a fifth harmonic of 159 hz. the speed of sound is 343

m/s. what is the wavelength of this sound
Physics
1 answer:
gogolik [260]4 years ago
6 0

Answer:

The wavelength is 2.16 m.

Explanation:

Given the speed of the sound = 343 m/s

Trombone generate the frequency = 159 Hz

Now we have to find the wavelength of the sound. Here, we can find the wavelength by dividing the speed of the sound with frequency.

The wavelength of the sound = Speed of sound/frequency

Wavelength of the sound = 343 / 159 = 2.16 m

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If you apply an unbalanced force to this object it will ______. Mention all that will apply: change velocity, accelerate, change
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Answer:

All of them: change velocity, accelerate, change position

Explanation:

We can answer this question by using Newton's second law:

F = ma

where

F is the net force on the object

m is the mass of the object

a is the acceleration

We notice that when there is an unbalanced force on the object, F\neq 0, and therefore

a\neq 0

whcih means that the object will accelerate.

But acceleration is the rate of change of velocity, v:

a=\frac{\Delta v}{\Delta t}

And so,

\Delta v \neq 0

which means that the object will change velocity.

If the object is changing velocity, this means that it is also moving: therefore, the position of the object must be changing, so also the option "change position" is correct.

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How do igneous rocks differ from each other.
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Which statement is true about acceleration?
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1. Some ripples spread across a pond with a frequency of 5 Hz. How much would be the period of these ripples.
Scilla [17]

1)The period of these ripples will be 0.2 sec.

2)The time period of sound wave will be 100 Hz.

3)The frequency of the sound wave will be 5×10⁶ Hz.

<h3>What is frequency?</h3>

Frequency is defined as the number of repetitions of a wave occurring waves in 1 second.

Frequency is given by the formula as,

Frequency of  ripples (f₁)=5 Hz

The period of these ripples will be;

T₁=1/f₁

T₁=1/5

T₁=0.2 sec

The time period of sound wave (T)=0.01 seconds

The time period of sound wave;

f=1/T

f=1/0.01

f=100 Hz

Time period of A radio wave = 0.0000002 seconds

The frequency of the sound wave is;

f=1/T

f=1/0.0000002

f=5×10⁶ Hz

Hence,the period of these ripples will be 0.2 sec.

To learn more about the frequency, refer to the link;

brainly.com/question/14926605

#SPJ1

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