Voltage = current(I) * resistance (R)
V = 18
R = 6
18 = I * 6
I = 18/6 = 3 Amps or D
Answer:

Explanation:
<u>Given:</u>
- Mass,
- Velocity,

where,
are the uncertainties in mass and velocity respectively.
The kinetic energy is given by

The uncertainty in kinetic energy is given as:

Answer: The magnetic field of a bar magnet is strongest at either pole of the magnet. It is equally strong at the north pole compared with the south pole. The force is weaker in the middle of the magnet and halfway between the pole and the center. So it would be D.
Answer:
I think the answers March 21
4
Just divide 12 by 3, so if it takes 3 seconds, then every second, it goes up 4.