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Elis [28]
3 years ago
11

Where more of hydrogen are contained in 90 g of water or in 80 g of methane

Chemistry
1 answer:
Lynna [10]3 years ago
7 0
Methane.

Water - H2O
Methane - CH4

Methane has 2 more hydrogens than water.
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What is 1.0 x 10^4 L in nL?
Vlada [557]

Answer:

= 10000000000000 Nanoliters

Explanation:

1.0 x (10^4) L =

10 000 L

10 000L converted into Nanoliters

= 10000000000000 Nanoliters

Hope this helps

6 0
3 years ago
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Luba_88 [7]

Answer:

yes u are correct as it define that

7 0
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What is the name of the tide when the sun, moon, and earth are all aligned, causing the greatest pull for highest and lowest tid
Tasya [4]

Answer:

spring tide

Explanation:

When the sun, moon, and Earth are in alignment (at the time of the new or full moon), the solar tide has an additive effect on the lunar tide, creating extra-high high tides, and very low, low tides — both commonly called spring tide

6 0
3 years ago
Read 2 more answers
Silver nitrate has lattice energy of -820kj/mol and a heat of solution of +22.6 kj/mol. calculate the heat of hydration for silv
Genrish500 [490]

Lattice energy = -820 kJ/mole

Heat of solution = +22.6 KJ/mole

Lattice breakdown is and endothermic reaction during the formation of solution

And hydration is an exothermic reaction as ions interact with solvent molecules

By using the formula,

Enthalpy of solution = Lattice energy + hydration energy

Now put the values and calculate,

+22.6 kj/mole = + 820 kj/mole + hydration energy

Hydration energy = 22.6 Kj/mole – 820 Kj/mole

Hydration energy= -797.4 Kj/mole


3 0
4 years ago
Determine the mole fractions and partial pressures of CO2, CH4, and He in a sample of gas that contains 1.20 moles of CO2, 1.79
BARSIC [14]

Answer :  The mole fraction and partial pressure of CH_4,CO_2 and He gases are, 0.267, 0.179, 0.554 and 1.54, 1.03 and 3.20 atm respectively.

Explanation : Given,

Moles of CH_4 = 1.79 mole

Moles of CO_2 = 1.20 mole

Moles of He = 3.71 mole

Now we have to calculate the mole fraction of CH_4,CO_2 and He gases.

\text{Mole fraction of }CH_4=\frac{\text{Moles of }CH_4}{\text{Moles of }CH_4+\text{Moles of }CO_2+\text{Moles of }He}

\text{Mole fraction of }CH_4=\frac{1.79}{1.79+1.20+3.71}=0.267

and,

\text{Mole fraction of }CO_2=\frac{\text{Moles of }CO_2}{\text{Moles of }CH_4+\text{Moles of }CO_2+\text{Moles of }He}

\text{Mole fraction of }CO_2=\frac{1.20}{1.79+1.20+3.71}=0.179

and,

\text{Mole fraction of }He=\frac{\text{Moles of }He}{\text{Moles of }CH_4+\text{Moles of }CO_2+\text{Moles of }He}

\text{Mole fraction of }He=\frac{3.71}{1.79+1.20+3.71}=0.554

Thus, the mole fraction of CH_4,CO_2 and He gases are, 0.267, 0.179 and 0.554 respectively.

Now we have to calculate the partial pressure of CH_4,CO_2 and He gases.

According to the Raoult's law,

p_i=X_i\times p_T

where,

p_i = partial pressure of gas

p_T = total pressure of gas  = 5.78 atm

X_i = mole fraction of gas

p_{CH_4}=X_{CH_4}\times p_T

p_{CH_4}=0.267\times 5.78atm=1.54atm

and,

p_{CO_2}=X_{CO_2}\times p_T

p_{CO_2}=0.179\times 5.78atm=1.03atm

and,

p_{He}=X_{He}\times p_T

p_{He}=0.554\times 5.78atm=3.20atm

Thus, the partial pressure of CH_4,CO_2 and He gases are, 1.54, 1.03 and 3.20 atm respectively.

4 0
3 years ago
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