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cluponka [151]
2 years ago
11

What conditions are needed to prevent iron from rusting?​

Chemistry
1 answer:
yulyashka [42]2 years ago
3 0
9 Ways to Prevent Rust
Use an Alloy. Many outdoor structures, like this bridge, are made from COR-TEN steel to reduce the effects of rust. ...
Apply Oil. ...
Apply a Dry Coating. ...
Paint the Metal. ...
Store Properly. ...
Galvanize. ...
Blueing. ...
Powder Coating.
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Iron and vanadium both have the BCC crystal structure and V forms a substitutional solid solution for concentrations up to appro
Hatshy [7]

Answer:

The unit cell edge length for the alloy is 0.288 nm

Explanation:

Given;

concentration of vanadium, Cv = 8 wt%

concentration of iron, Cfe = 92 wt%

density of vanadium = 6.11 g/cm³

density of iron = 7.86 g/cm³

atomic weight of vanadium, Av = 50.94 g/mol

atomic weight of iron, Afe= 55.85 g/mol

Step 1: determine the average density of the alloy

\rho _{Avg.} = \frac{100}{\frac{C_v}{\rho _v} + \frac{C__{Fe}}{\rho _{Fe}} }

\rho _{Avg.} = \frac{100}{\frac{8}{6.11} + \frac{92}{7.86} } = 7.68 \ g/cm^3

Step 2: determine the average atomic weight of the alloy

A _{Avg.} = \frac{100}{\frac{C_v}{A _v} + \frac{C__{Fe}}{A _{Fe}} }

A _{Avg.} = \frac{100}{\frac{8}{50.94} + \frac{92}{55.85} } = 55.42 \ g/mole

Step 3: determine unit cell volume

V_c=\frac{nA_{avg.}}{\rho _{avg.} N_a}

for a BCC crystal structure, there are 2 atoms per unit cell; n = 2

V_c=\frac{2*55.42}{ 7.68*6.022*10^{23}} = 2.397*10^{-23} \ cm^3/cell

Step 4: determine the unit cell edge length

Vc = a³

a = V_c{^\frac{1}{3} }\\\\a = (2.397*10^{-23}}){^\frac{1}{3}}\\\\a = 2.88 *10^{-8} \ cm= 0.288 nm

Therefore, the unit cell edge length for the alloy is 0.288 nm

4 0
3 years ago
What are the most of the elements in the periodic table
vaieri [72.5K]

Answer:

Most of the elements in the periodic table are <u><em>metals</em></u>.

Hope that helps. x

5 0
2 years ago
Read 2 more answers
Which of the following is NOT a homogeneous mixture? *<br> koolaid<br> soda<br> tea<br> water
Wittaler [7]

Answer:

water

Explanation:

Because it does not have more than one component.

4 0
3 years ago
The map shows watersheds with a high potential for soil, nitrogen, and pesticide runoff. If you were in charge of handling the p
Yuri [45]

Answer:

Here are some possible answers:

Why are watersheds in the Midwest more prone to pollution in than other areas in the country?

What are the current flood and pollution control measures in place in high-risk regions?

What are the flaws with the systems used to control pollution in high-risk regions?

What can the officials and scientists in one region learn from those in another region?

What would the effects on residents be if we made changes to current flood and pollution control measures?

Explanation:

When manure or commercial fertilizers enter surface water, the nutrients they release stimulate microorganism growth. The growth and reproduction of microorganisms reduce the dissolved oxygen content of the water body. Without sufficient dissolved oxygen in surface water, fish and other aquatic species suffocate.

7 0
3 years ago
Potassium hydrogen phthalate is a solid, monoprotic acid frequently used in the laboratory to standardize strong base solutions.
Norma-Jean [14]

2 KHP(aq) + Ba(OH)_{2}(aq) ---> KP_{2}Ba (aq) + 2 H_{2}O (l)\

Moles of Ba(OH)_{2}=0.483 \frac{mol}{L} * 28.5 mL *\frac{1 L}{1000mL}  = 0.0138 mol Ba(OH)_{2}

Mass of KHP = 0.0138 mol Ba(OH)_{2} * \frac{2 mol KHP}{1 mol Ba(OH)_{2}}  * \frac{204.22 g KHP}{1mol KHP}

= 5.64 g KHP

6 0
3 years ago
Read 2 more answers
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