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iren2701 [21]
3 years ago
13

We can model the motion of a dragonfly's wing as simple harmonic motion. The total distance between the upper and lower limits o

f motion of the wing tip is 1.0 cm. The wing oscillates at 40 Hz. What is the maximum speed of the wing tip?
Physics
1 answer:
PtichkaEL [24]3 years ago
7 0

Answer:

The maximum speed of the wing tip is 1.25 m/s

Explanation:

In simple harmonic motion, the body experiences a restoring force whose magnitude is directly proportional to the distance from its mean position and its direction is towards the mean position.

The speed in the case of simple harmonic motion is given by the equation :

v = Aωsinωt

Here A is maximum displacement, t is time and ω is the angular frequency of oscillation.

For maximum speed, sinωt = 1 . So, the above equation becomes:

v = Aω

But, ω = 2πf , here f is the frequency of oscillation. So,

v = A x 2πf      .....(1)

In this problem,

Frequency of oscillation, f = 40 Hz

Total distance between the upper and lower limits of motion of wing tip is equal to the twice of maximum displacement of the wing tip from the equilibrium position, i.e. ,

2 x A = 1 cm

A = 0.5 cm = 0.5 x 10⁻² m

Substitute the value of f and A in equation (1).

v=2\pi\times40\times0.5\times10^{-2}

v = 1.25 m/s

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When a cube is inscribed in a sphere of radius r, the length Lof a side of the cube is . If a positive point charge Qis placed a
Nana76 [90]

Answer:

  Ф_cube /Ф_sphere = 3 /π

Explanation:

The electrical flow is

      Ф = E A

where E is the electric field and A is the surface area

Let's shut down the electric field with Gauss's law

       Фi = ∫ E .dA = q_{int} / ε₀

the Gaussian surface is a sphere so its area is

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the charge inside is

        q_{int} = Q

we substitute

       E 4π r² = Q /ε₀

       E = 1 / 4πε₀   Q / r²

To calculate the flow on the two surfaces

* Sphere

       Ф = E A

        Ф = 1 / 4πε₀  Q / r² (4π r²)

        Ф_sphere = Q /ε₀

* Cube

Let's find the side value of the cube inscribed inside the sphere.

In this case the radius of the sphere is half the diagonal of the cube

          r = d / 2

We look for the diagonal with the Pythagorean theorem

         d² = L² + L² = 2 L²

         d = √2 L

         

we substitute

          r = √2 / 2 L

          r = L / √2

          L = √2  r

now we can calculate the area of ​​the cube that has 6 faces

          A = 6 L²

          A = 6 (√2  r)²

          A = 12 r²

the flow is

          Ф = E A

          Ф = 1 / 4πε₀  Q/r²  (12r²)

          Ф_cubo = 3 /πε₀  Q

the relationship of these two flows is

         Ф_cube /Ф_sphere = 3 /π

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An inductor is connected to the terminals of a battery that has an emf of 16.0 V and negligible internal resistance. The current
balu736 [363]

Answer:

(a) The resistance R of the inductor is 2480.62 Ω

(b) The inductance L of the inductor is 1.67 H

Explanation:

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Part (a) The resistance R of the inductor

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Part (b)  the inductance L of the inductor

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where;

L is the inductance

R is the resistance of the inductor

t is time

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