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4 years ago

Heat will flow from a hot object to a cold object until the objects reach

Physics

2 answers:

OverLord2011 [107]4 years ago

7 0

Answer: A equilibrium

Explanation:

leonid [27]4 years ago

3 0

Answer:

(The first law of thermodynamics) When you put a hot object in contact with a cold one, heat will flow from the warmer to the cooler. As a result, the warmer one will usually cool down and the cooler one will usually warm up. Eventually, they will reach the same temperature and heat flow will stop.

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The ball will oscillate along the z axis between z=dz=d and z=−dz=−d in simple harmonic motion. What will be the angular frequen

Eddi Din [679]

Answer:

$\omega = \sqrt{\dfrac{kq_0Q}{ma^3} }$

Explanation:

Additional information:

The ball has charge $-q_0$ , and the ring has positive charge $+Q$ distributed uniformly along its circumference.

The electric field at distance $z$ along the z-axis due to the charged ring is

$E_z= \dfrac{kQz}{(z^2+a^2)^{3/2}}.$

Therefore, the force on the ball with charge $-q_0$ is

$F=-q_oE_z$

$F=- \dfrac{kq_0Qz}{(z^2+a^2)^{3/2}}$

and according to Newton's second law

$F=ma=m\dfrac{d^2z}{dz^2}$

substituting $F$ we get:

$- \dfrac{kq_0Qz}{(z^2+a^2)^{3/2}}=m\dfrac{d^2z}{dz^2}$

rearranging we get:

$m\dfrac{d^2z}{dz^2}+ \dfrac{kq_0Qz}{(z^2+a^2)^{3/2}}=0$

Now we use the approximation that

$z^2+a^2\approx a^2$ (we use this approximation instead of the original $d^2+a^2\approx a^2$ since $z$ , our assumption still holds )

and get

$m\dfrac{d^2z}{dz^2}+ \dfrac{kq_0Qz}{(a^2)^{3/2}}=0$

$m\dfrac{d^2z}{dz^2}+ \dfrac{kq_0Qz}{a^{3}}=0$

Now the last equation looks like a Simple Harmonic Equation

$m\dfrac{d^2z}{dz^2}+kz=0$

where

$\omega=\sqrt{ \dfrac{k}{m} }$

is the frequency of oscillation. Applying this to our equation we get:

$m\dfrac{d^2z}{dz^2}+ \dfrac{kq_0Q}{a^{3}}z=0\\\\m=m\\\\k= \dfrac{kq_0Q}{a^{3}}$

$\boxed{\omega = \sqrt{\dfrac{kq_0Q}{ma^3} }}$

5 0

4 years ago

During the power stroke energy released by combustion generates the force that:_______.

Inessa05 [86]

Explanation:

An IC engines means an Internal Combustion engine. Here, the combustion takes place in side a chamber or a cylinder internally, hence it is known as internal combustion engine.

Combustion is the process where oxygen reacts with the fuel and it burns to produce a large amount of force and heat. In each revolution of the crank, the engine creates a power stroke when the piston goes from the bottom dead center to the top dead center.

During each power stroke, the energy released forces the piston down and the crankshaft is rotated.

8 0

3 years ago

Which measure of dispersion indicates the extent to which each individual score in a data set varies from the mean of that set?

vichka [17]

Answer:

Option 2 - Standard deviation

Explanation:

To find : Which measure of dispersion indicates the extent to which each individual score in a data set varies from the mean of that set?

Solution :

Standard deviation is defined as,

It is a mathematical measure that is used to evaluate the difference between the mean value of a set of number and each value in the group.

It is calculated as the square root of variance by determining the variation between each data point relative to the mean.

The measure of dispersion that indicates how much scores in a sample vary around the mean of the sample is the standard deviation.

Therefore, option 2 is correct.

3 0

3 years ago

A string along which waves can travel is 4.36 m long and has a mass of 222 g. The tension in the string is 60.0 N. What must be

lora16 [44]

Answer:

frequency is 195.467 Hz

Explanation:

given data

length L = 4.36 m

mass m = 222 g = 0.222 kg

tension T = 60 N

amplitude A = 6.43 mm = 6.43 × $10^{-3}$ m

power P = 54 W

to find out

frequency f

solution

first we find here density of string that is

density ( μ )= m/L ................1

μ = 0.222 / 4.36

density μ is 0.050 kg/m

and speed of travelling wave

speed v = √(T/μ) ...............2

speed v = √(60/0.050)

speed v = 34.64 m/s

and we find wavelength by power that is

power = μ×A²×ω²×v / 2 ....................3

here ω is wavelength put value

54 = ( 0.050 ×(6.43 × $10^{-3}$ )²×ω²× 34.64 ) / 2

0.050 ×(6.43 × $10^{-3}$ )²×ω²× 34.64 = 108

ω² = 108 / 7.160 × $10^{-5}$

ω = 1228.16 rad/s

so frequency will be

frequency = ω / 2π

frequency = 1228.16 / 2π

frequency is 195.467 Hz

7 0

4 years ago

What can reduce a machines efficiency

algol [13]

Answer:

its power.

Explanation:

6 0

3 years ago

Read 2 more answers